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AlladinOne [14]
3 years ago
7

What is the 100th term of the sequence with a1=222 and d=-5

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

--273

Step-by-step explanation:

100th term is equal a1 + 99d so

100th term = 222 + (-5×99) = -273

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(2+5x)9= combine like terms
rodikova [14]

Answer:

18+45x

Step-by-step explanation:

4 0
3 years ago
Solve for x: <br> (125^2x)(5x) = 25^3
olga nikolaevna [1]
(125^2x)(5x) = 25^3
(15625x)(5x)=15625
<span>78125x=15625
</span>x=5

Hope I helped ;D
6 0
3 years ago
Arthur bought a life insurance policy at $10.98 per month for a 20 year term. What will he pay over 20 years for the premium?
mrs_skeptik [129]
D is the right answer
3 0
3 years ago
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(x+y)^2 (x2+2xy+y2) pleas show all work
lakkis [162]

Answer:

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

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​​ y+6x

​2

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Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

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({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x

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​​ )(x

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2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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​​ (x

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​​ +2xy+y

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​​ )+y

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​​ (x

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3 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2xy(x

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​​ +2xy+y

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​​ )+y

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4 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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​​ y

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​​ (x

​2

​​ +2xy+y

​2

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5 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ x

​2

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6 Collect like terms.

{x}^{4}+(2{x}^{3}y+2{x}^{3}y)+({x}^{2}{y}^{2}+4{x}^{2}{y}^{2}+{x}^{2}{y}^{2})+(2x{y}^{3}+2x{y}^{3})+{y}^{4}x

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​​ y

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​​ )+y

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​​  

7 Simplify.

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

​​ +4x

​3

​​ y+6x

​2

​​ y

​2

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7 0
3 years ago
Read 2 more answers
Please help me with this??
Ludmilka [50]

Answer:

c, d and f are rational numbers

Step-by-step explanation:

c) 3\sqrt{5}*2\sqrt{5}=3*2*\sqrt{5*5} = 3*2*5 = 30\\\\\\d)  \dfrac{3\sqrt{5}}{2\sqrt{5}}= \dfrac{3}{2}\\\\\\f)  \dfrac{2\sqrt{5}}{3\sqrt{5}}= \dfrac{2}{5}

6 0
2 years ago
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