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trapecia [35]
3 years ago
10

Hey can anyone pls help me out in dis math problem real quick I WILL MARK U AS BRAINLIEST!!!!!!!!

Mathematics
2 answers:
lbvjy [14]3 years ago
6 0

<em>Answer:</em>

<em />

<em>1.) 4.87831517751 </em>

<em>2.) 12.124355653 </em>

<em />

<em>Step-by-step explanation:</em>

<em>A.)</em>

<em>The diagonal is 4.87831517751  FT long. </em>

<em>The diagonal equals the square root of the width squared plus the height squared.</em>

<em>Square root of 2 is 1.41421356237 </em>

<em>Square root of 12 is 3.46410161514 </em>

<em>3.46410161514  + 1.41421356237  = 4.87831517751 .</em>

<em>B.) </em>

<em>The diagonal is 12.124355653 CM long. </em>

<em>The main diagonal of any cube can be found by multiplying the length of one side by the square root of 3.</em>

<em>Square root of 3 is 1.73205080757</em>

<em>1.73205080757 x 7 = 12.124355653 </em>

Alenkinab [10]3 years ago
5 0

Answer:

14.4 my guy

Step-by-step explanation:

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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

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Help me with my problems<br><br>(sorry if the text is small)
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