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ololo11 [35]
3 years ago
10

A manufacturer of all-in-one printers is concerned that the warranty costs for a particular printer model exceed the amount expe

cted by the company. Based on a review of completed warranty claims, the distribution of the warranty cost per claim is skewed to the right with mean $150 and standard deviation $50. A random sample of 25 completed warranty claims is selected, and the sample mean cost is recorded. Suppose the process of selecting a random sample of 25 completed warranty claims and recording the sample mean cost is repeated for a total of 100 samples. Which of the following best describes a dotplot created from the 100 sample means?
(A) The dotplot has the same shape as the distribution of the population with mean $150 and standard deviation $25.
(B) The dotplot has the same shape as the distribution of the population with mean $150 and standard deviation $50.
(C) The dotplot has the same shape as the distribution of the population with mean $150 and standard deviation $100.
(D) The dotplot is closer to approximately normal than the distribution of the population with mean $150 and standard deviation $10.
(E) The dotplot is closer to approximately normal than the distribution of the population with mean $150 and standard deviation $50.
Mathematics
1 answer:
mariarad [96]3 years ago
3 0

Answer: D. The dotplot is closer to approximately normal than the distribution of the population with mean $150 and standard deviation $10.

Step-by-step explanation:

Based on the dotplot created from the 100 sample, the dotplot is closer to approximately normal than the distribution of the population with mean $150 and standard deviation $10.

The mean of the sampling distribution is just exactly like the population mean. On the other hand, the standard deviation will be: = 50/✓25 = 50/5 = 10

Therefore, the correct option is D.

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Ismael has a set of 5 solar panels and Ben has a set of 6 smaller solar panels. Each set of panels produce the same amount of en
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Answer:

  Ben's

Step-by-step explanation:

If E is the amount of energy that each full set of panels produces, then ...

  3 of Ismael's 5 panels produce 3/5E

  4 of Ben's 6 panels produce 4/6E

We can compare these fractions when they have a common denominator.

  3/5E = 18/30E . . . . energy from Ismael's panels

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3 years ago
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3 years ago
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Find the surface area of the rectangular prism
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Answer:

185.68 cm3

Step-by-step explanation:

SA = 2 (L x W) + 2 (L x H) + 2 (W x H)

     = 2 (8.2 x 3.4) + 2 (8.2 x 5.6) + 2 (3.4 x 5.6)

     = 2 (27.88)      + 2 (45.92)      + 2 (19.04)

     =     55.76       +     91.84         +     38.08

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4 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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