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2 years ago

Help me find the right angles URGENT !!

Mathematics

1 answer:

sasho [114]2 years ago

8 0

Answer:

q is around 85-89 and S is 91-95

Step-by-step explanation:

sorry i dont have a protractor on me this is the best i can do

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A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Item a:

The estimate is $\pi = 0.213 - 0.195 = 0.018$ .

The sample size is <u>n for which M = 0.03</u>, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}$

$\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2$

$n = 53.1$

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence $\pi = 0.05$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 751.7$

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0

1 year ago

Which of the following is the result of expanding the series 2(17X+2)?

labwork [276]

The third one I think but I am not sure

7 0

2 years ago

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What’s the circumference of circles

ale4655 [162]

Answer:

62.83185

Step-by-step explanation:

C=2πr=2·π·10≈62.83185

6 0

1 year ago

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Please help me with this problem. I'm stuck!!

mihalych1998 [28]

$\bf S(t)=4\pi \left( \cfrac{3}{8}t^4 \right)^2\impliedby \textit{distributing the exponent}
\\\\\\
S(t)=4\pi \left( \cfrac{3^2}{8^2}t^{4\cdot 2} \right)\implies S(t)=4\pi \cdot \cfrac{9t^8}{64}\implies S(t)=\cfrac{4}{64}\cdot \cfrac{9\pi t^8}{1}
\\\\\\
S(t)=\cfrac{1}{16}\cdot \cfrac{9\pi t^8}{1}\implies S(t)=\cfrac{9\pi t^8}{16}$

6 0

2 years ago

I am confused on this question

kaheart [24]

<h3>Answer: Around 4681 grills</h3>

============================================

Explanation:

x = number of years

y = number of grills sold

The equation we'll use is the exponential equation $y = 3300(1.06)^x$

The 3300 of course is the initial amount sold. The 1.06 as the base indicates that the sales increase by 6% each year. Think of it the 1.06 as 1+0.06 = 100% + 6%

If we plugged x = 0 into that equation, then we get

$y = 3300(1.06)^x = 3300(1.06)^0 = 3300$

which helps confirm the correct equation.

----------------

Now plug in x = 6 to find the sales for year 6.

$y = 3300(1.06)^x = 3300(1.06)^6 \approx 4681.11 \approx 4681$

The projected sales for year 6 are about 4681 grills. This is an estimate based on the assumption that the sales will increase by 6% each year. Of course, the reality is that things aren't always so simple like this (but it should give a fairly good idea of what's going on).

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1 year ago

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