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Setler [38]
2 years ago
15

Help me find the right angles URGENT !!

Mathematics
1 answer:
sasho [114]2 years ago
8 0

Answer:

q is around 85-89 and S is 91-95

Step-by-step explanation:

sorry i dont have a protractor on me this is the best i can do

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John shot a toy rocket into the air. Consider the graph below which shows the relationship between the height of the rocket from
EleoNora [17]
<h2>The height of the rocket increases for some time and then decreases for some time.</h2>

The height from the ground increases from 4 to 26, then decreases from 26 to 0.

Why the others are wrong.

A. The height of the rocket changes at a constant rate for the entire time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

C. The height of the rocket remains constant for some time.

The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.

D. The height of the rocket decreases for some time and then increases for some time.

This implies the graph decreases first then increases. However, the rocket will increase, then decrease.

5 0
3 years ago
PLEASE HELP! 35 POINTS
nignag [31]
no solution, they are all the same line
4 0
2 years ago
Please Solve The Triangle for x
telo118 [61]
What triangle? Is there one on here?
4 0
2 years ago
Stephanie had a total of 80 pieces of $ 2 and $ 10 notes. After spending 2/5 of her $ 2 notes and 8 pieces of her $ 10 notes, sh
Ghella [55]

Answer:

$440

Step-by-step explanation:

notes $2 - n

notes $10 - m

n + m = 80 ----------> m = 80 - n

1 - 2/5 = 3/5

\frac{3}{5} * n = m - 8

\frac{3}{5} * n = 80 - n - 8 \\\\\frac{3}{5} * n + n = 72\\\\\frac{8}{5} * n = 72\\n = 45 \\m = 35\\

45 * $2 + 35 * $10 = 90 + 350 = $440

3 0
2 years ago
Kacey is making a bracelet that is 8 inches long. She uses 1 green bead at each end of the bracelet. She also uses 1 green bead
Effectus [21]

Answer:

The answer would be C. 5

Step-by-step explanation:

5 0
3 years ago
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