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lana [24]
3 years ago
13

Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus

chloride.
2P +3Cl2 2PCl3

How much chlorine reacted with the phosphorus?

15.5 g
17.7 g
35.4 g
66.4 g
Chemistry
2 answers:
melomori [17]3 years ago
5 0

Answer: 35.4 g

2 moles of phosphorous chloride are produced by = 3 moles of  

Thus 0.37 moles of phosphorous chloride are produced by= of  

Mass of  

Thus 35.4 g of chlorine reacted with the phosphorus

melomori [17]3 years ago
4 0
Answer 35.4g
That’s the answer
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2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
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Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

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Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

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                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

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At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

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Answer:

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