Diatomic gases contain covalent bond
Answer:
a)M=0.20/(0.335*0.1025)= 0.20/ 0.034 = 5.88 g/mol
b) if 0.100g is used instead of 0.200g
M = 0.1 / 0.034 = 2.94 hence the molar mass will be too low
Explanation:
0.2000 gHZ gives 100ml acid solution
33.5 ml of 0.1025 M NaOH is required to prepare it
the moles = mass / molar mass
mass = 0.200 gHZ
moles = 0.0335*100 * 0.1025 = 0.034
therefore molar mass = mass / moles
M=0.20/(0.335*0.1025)= 0.20/ 0.034 = 5.88
if 0.100g is used instead of 0.200g
M = 0.1 / 0.034 = 2.94 hence the molar mass will be too low
Answer:
The metal has a heat capacity of 0.385 J/g°C
This metal is copper.
Explanation:
<u>Step 1</u>: Data given
Mass of the metal = 21 grams
Volume of water = 100 mL
⇒ mass of water = density * volume = 1g/mL * 100 mL = 100 grams
Initial temperature of metal = 122.5 °C
Initial temperature of water = 17°C
Final temperature of water and the metal = 19 °C
Heat capacity of water = 4.184 J/g°C
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<u>Step 2: </u>Calculate the specific heat capacity
Heat lost by the metal = heat won by water
Qmetal = -Qwater
Q = m*c*ΔT
m(metal) * c(metal) * ΔT(metal) = - m(water) * c(water) * ΔT(water)
21 grams * c(metal) *(19-122.5) = -100 * 4.184 * (19-17)
-2173.5 *c(metal) = -836.8
c(metal) = 0.385 J/g°C
The metal has a heat capacity of 0.385 J/g°C
This metal is copper.
Answer:
Explanation:
The expression for the work done is:
Where,
W is the amount of work done by the gas
R is Gas constant having value = 8.314 J / K mol
T is the temperature
P₁ is the initial pressure
P₂ is the final pressure
Given that:
T = 300 K
P₁ = 10 bar
P₂ = 1 bar
Applying in the equation as:
It depends. many of the websites i see answering the questions are all over the place, but good luck.
