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dimaraw [331]
3 years ago
10

What is the process called to prepare a ceramic by heating a slurry of a powder of an inorganic substance in water to a very hig

h temperature under pressure
Chemistry
1 answer:
Zolol [24]3 years ago
8 0

<u>Answer:</u> The process that is used to prepare ceramic is sintering.

<u>Explanation:</u>

Sintering is defined as the process in which number of particles are fused together to form one solid mass by the applying pressure at high temperatures.

Ceramic is an material that is made by taking mixtures of clay, earthen elements, powders and water.

When this mixture (slurry of the powders) is heated at a very high temperature and under high pressure, ceramic is formed.

Hence, the process that is used to prepare ceramic is sintering.

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For many purposes we can treat propane
dangina [55]

Answer:The volume increases by 11%

Explanation:

When the pressure is decreased, the volume must definitely increase, to maintain the same pressure, the temperature must then also be increased as we see in the question. The volume was increased just as the pressure decreased and the temperature had to be increased to maintain a constant pressure. We have applied the general gas equation in solving the problem.

3 0
4 years ago
Which of the following equations does not represent a redox reaction?
bija089 [108]

Answer:

a. NH3+ HCl → NH4Cl

c. 2O3 → 3O2

Explanation:

A redox reaction is a reaction in which there is loss or gain of electrons. As  a result of that , there is a change in the oxidation number of the species involved in the reaction.

If we look at the species shown in the answer, there isn't any change in oxidation number as we move from left to right hence they are not redox reactions.

Redox reactions lead to change in oxidation number of species from left to right.

4 0
3 years ago
How many grams of sodium chloride decompose to yield 15 grams of chlorine gas?
defon

Answer:

24.6g of NaCl

Explanation:

Expression of the reaction:

            2NaCl →  2Na  +  Cl₂

Given parameters:

Mass of Cl₂  = 15g

Unknown:

Mass of NaCl  = ?

Solution:

To solve this problem, we have to use mole relationships.

 Find the number of moles of the mass of the given specie;

    Number of moles  = \frac{mass}{molar mass}  

     Molar mass of Cl₂  = 2(35.5) = 71g/mol

   Number of moles  = \frac{15}{71}   = 0.21mole

Now;

 From the balanced reaction equation;

        1 mole of Cl₂ is produced from 2 moles of NaCl;

      0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl

So,

  Mass of NaCl = number of moles x molar mass

    Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol

 Mass of NaCl  = 0.42 x 58.5 = 24.6g of NaCl

8 0
3 years ago
How are half life and radioactive decay related
hoa [83]

Answer : Half life and radioactive decay are inversely proportional to each other.

Explanation :

The mathematic relationship between the half-life and radioactive decay :

N=N_oe^{-\lambda t}              ................(1)

where,

N = number of radioactive atoms at time, t

N_o = number of radioactive atoms at the beginning when time is zero

e = Euler's constant = 2.17828

t = time

\lambda = decay rate

when t=t_{1/2} then the number of radioactive decay become half of the initial decay atom i.e N=\frac{N_o}{2}.

Now substituting these conditions in above equation (1), we get

\frac{N_o}{2}=N_oe^{-\lambda t_{1/2}}

By rearranging the terms, we get

\frac{1}{2}=e^{-\lambda t_{1/2}}

Now taking natural log on both side,

ln(\frac{1}{2})=-\lambda \times t_{1/2}

By rearranging the terms, we get

t_{1/2}=\frac{0.693}{\lambda}

This is the relationship between the half-life and radioactive decay.

Hence, from this we conclude that the Half life and radioactive decay are inversely proportional to each other. That means faster the decay, shorter the half-life.

3 0
3 years ago
Help me please!!
WINSTONCH [101]

Answer:

663 g

Explanation:

Step 1: Write the balanced equation

2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃

Step 2: Calculate the moles corresponding to 825 L of CO₂

At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.

825 L × 1 mol/22.4 L = 36.8 mol

Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂

The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.

Step 4: Calculate the mass corresponding to 36.8 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

36.8 mol × 18.02 g/mol = 663 g

3 0
3 years ago
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