Which one of the following molecules would be most polar?

1 answer:

4 0

This question is quite a controversial one, because three of the options represented above are very similar, but due to the fact that there is a HF, which is even more polar that water, it is getting clear. So, the right answer is definitely the first option, because <span>HF belongs to acids that are very polar compounds.</span>

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How Could Spectroscopy Be Used to Distinguish Between the Following

skelet666 [1.2K]

Spectroscopy be used to distinguish between the following is the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

<h3>What is spectroscopy?</h3>

Spectroscopy is the study of emission or absorption of light. It is used to study the structure of atoms and molecules.

The three types of spectroscopy are:

atomic absorption spectroscopy (AAS)
atomic emission spectroscopy (AES)
atomic fluorescence spectroscopy (AFS)

Thus, the correct option is B, the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.

Learn more about spectroscopy

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5 0

2 years ago

Explain why the lattice energy of CaSe is approximately 4 times as large as that of KBr. Check all that apply. Check all that ap

Elza [17]

Answer:

According to Coulomb’s law, the Ca and Se ions have 4 times the attractive force (2+ × 2-) than that of the K and Br ions (1+ × 1-).

Explanation:

From Coulomb's law, the attractive force between calcium and selenium ions is four times the attractive force between potassium and bromide ions.

This has something to do with size and magnitude of charge. Calcium ions and selenide ions are smaller and both carry greater charge magnitude than potassium and bromide ions. This paves way for greater electrostatic attraction between them when the distance of the charges apart is minimal. Hence a greater lattice energy.

4 0

2 years ago

It's 32°F (0°C) outside under normal atmospheric conditions (1 atm) at a stunt

Korolek [52]

The volume of the balloon is approximately 2652 liters.

<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass ( $M$ ), in kilograms per kilomole, and mass of the gas ( $m$ ), in kilograms. The volume occupied by the gas ( $V$ ), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

$V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}$ (1)

Where:

$R_{u}$ - Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
$T$ - Temperature, in Kelvin
$P$ - Pressure, in kilopascals

If we know that $m = 0.239\,kg$ , $R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}$ , $T = 273.15\,K$ , $P = 101.325\,kPa$ and $M = 2.02\,\frac{kg}{kmol}$ , then the volume of the balloon is:

$V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}$