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olganol [36]
3 years ago
10

Which one of the following molecules would be most polar?

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
4 0
This question is quite a controversial one, because three of the options represented above are very similar, but due to the fact that there is a HF, which is even more polar that water, it is getting clear. So, the right answer is definitely the first option, because <span>HF belongs to acids that are very polar compounds.</span>
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Magnesium and Iodine will combine to make a compound. 
anygoal [31]
Magnesium and I think its MG12 for the other part
5 0
3 years ago
Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wo
kozerog [31]

Answer:

The correct answer is A Energy leaves the iron bar and enters the wood until the temperature are equal.

Explanation:

According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.

        Here iron bar is placed in wood block energy is transferred from iron bar to wood until the temperatures are equal.

7 0
4 years ago
When particles are removed volume will do what
DIA [1.3K]
Volume will decrease over time, the more particles removed, is making the volume decrease. 
7 0
3 years ago
Which metal cations form a white precipitate with both H2SO4(aq) and Na2S2O4(aq)? 1. Ba2+ 2. Sr2+ 3. Fe2+ 4. Cu2+
8090 [49]

Answer:

1. Ba2+ 2. Sr2+

Explanation:

When a solution contains the Barium ,Ba²⁺ ion or Strontium, Sr²⁺ ion, they reacts with either H₂SO₄(aq) or Na₂SO₄(aq) to produce a white precipitate of BaSO₄(s) and SrSO₄(s) respectively

The chemical reactions are given below

Ba²⁺ +  H₂SO₄(aq) ⇒ BaSO₄(s) + 2H⁺ (aq)

Ba²⁺ +  Na₂SO₄(aq) ⇒ BaSO₄(s) + 2Na⁺ (aq)

Sr²⁺ +  H₂SO₄(aq) ⇒ SrSO₄(s) + 2H⁺ (aq)

Sr²⁺ +  Na₂SO₄(aq) ⇒ SrSO₄(s) + 2Na⁺ (aq)

6 0
3 years ago
A solution with [ OH] of 5 x 10-3 has a pH of
CaHeK987 [17]

Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × 10^{-3} M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

<h3>At 298 K the dissociation constant of water is 10^{-14} </h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>

∴ pOH of the given solution = - log(5 × 10^{-3} = -0·699 + 3 = 2·301

   pH of the given solution = 14 - 2·301 = 11·699

∴ pH of the solution = 11·699                                  

8 0
4 years ago
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