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3 years ago

A person runs 10 laps around 400m track in 20 min.calculate the runners average velocity in m/s

Chemistry

1 answer:

Afina-wow [57]3 years ago

4 0

Explanation:

400×10=4000m

20×60=1200s

S=D÷T

S=4000÷1200

S=3.33m/s

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What is the pressure in a 5.00 L tank with 49.00 grams of oxygen gas at 350 K? ___atm

ziro4ka [17]

Answer:

The right answer is "8.81 atm".

Explanation:

Given:

V = 5.00 L

Mass = 4900 g

MW = 32 g/mol

T = 350 K

Now,

Number of moles will be:

$n = \frac{Mass}{MW}$

$=\frac{49.00}{32}$

$=1.53125 \ mole$

By using the ideal gas equation, we get

⇒ $PV=nRT$

or,

⇒ $P=\frac{nRT}{V}$

By substituting the values, we get

$=\frac{1.53125\times 0.0821\times 350}{5.00}$

$=\frac{44.1}{5.00}$

$=8.81 \ atm$

4 0

3 years ago

Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p

masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

Answer: The amount of liquid bromine produced is 4.79 moles.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, $(Br_2)$ = 159.8 g/mol

Putting values in above equation, we get:

$\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol$

Hence, the amount of liquid bromine produced is 4.79 moles.

6 0

3 years ago

_______ law states the volume of a definite quantity of dry gas is inversely proportional to the pressure, provided the temperat

nasty-shy [4]

Boyles law --i hope this helps

5 0

3 years ago

When C2H6(g) reacts with O2(g) according to the following reaction, 1.43×103 kJ of energy are evolved for each mole of C2H6(g) t

dezoksy [38]

Answer:

-2.86x10³ kJ

Explanation:

The enthalpy of a reaction (ΔH) is defined as the heat produced or consumed by a reaction. In the reaction:

2 C₂H₆(g) + 7 O₂(g) → 4 CO₂(g) + 6 H₂O(g)

The ΔH is the heat envolved in the reaction per 2 moles of C₂H₆. 1.43x10³ kJ are involved when 1 mole reacts. Thus, when 2 moles react, involved heat is:

1.43x10³ kJ ₓ 2 = 2.86x10³ kJ. As the reaction is a combustion reaction (Produce CO₂ and H₂O), the heat involved in the reaction is PRODUCED, that means ΔH is negative, -2.86x10³ kJ

8 0

3 years ago

Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen

MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

$C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O$