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Natali5045456 [20]
3 years ago
9

What is the affect of increasing the water's mass?how does it reflect it's temperature?

Chemistry
1 answer:
Nikolay [14]3 years ago
8 0
I assume what you're asking about is, how does the temperature changes when we increase water's mass, according the formula for heat ? 
Well the formula is : Q=m\cdot c\cdot \Delta t (where Q is heat, m is mass, c is specific heat and \Delta t is change in temperature. So according this formula, increasing mass will increase the substance's heat, but won't effect it's temperature since they are not related. Unless,  if you want to keep the substance's heat constant, in that case when you increase it's mass you will have to decrease the temperature
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How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

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3 years ago
What will happen to the chemical equilibrium if MgCl2 is added?
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2 years ago
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What is the compound formula for Ba2 and NO3–?
Dimas [21]

That would be the compound Ba(NO3)2. The Barium ion has a charge of 2+ so there are 2 NO3- ions in the formula to produce a neutral compound.

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3 years ago
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The human eye is a complex sensing device for visible light. The optic nerve needs a minimum of 2.0 × 10−17 J of energy to trigg
AveGali [126]
Number of photons can be calculated by dividing the needed energy by the energy per photon.

The minimum energy needed is given as 2 x 10^-17 joules
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Energy per photon = (<span>6.626 x 10^-34 x 3 x 10^8) / (475 x 10^-9)
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7 0
3 years ago
A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )

V_{2} = 0.000151 m^{3}

This is the final volume of the sample of gas.

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3 years ago
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