Answer:
50.41 feet
Step-by-step explanation:
Hypotenuse = length of ladder
31 = opposite side of angle
sin(angle) = (opposite)/(hypotenuse)
sin(78) = (36)/(hypotenuse)
hypotenuse = sin(78)/ (36)
hypotenuse = 50.41 feet
length of ladder = 50.41 feet
498+345 is the answer but you divide the 3 for base of 9
Answer: The equation is t(n) = 64(0.5)^n.
This is an example of an exponential equation because we are repeatedly multiplying the value by 1/2.
Exponential equation take the form of y = ab^x, where a is the starting amount and b is the rate.
In our case, we are starting with 64 and reducing half (0.5) of the teams each week.
This makes our equation: y = 64(0.5)^x
There are 1680 digits 2, 0, 2, and 2 as a 4-digit consecutively ordered block with no other digits between them
<h3>How to determine the selection</h3>
To determine the number of whole numbers, the following must be true
Case 1: If the sequence starts from the first digit
- The first digit can be any of the three 2's (i.e. 3 digits)
- The second digit can only be 0
- The third digit can be any of the remaining 2's (i.e. 2 digits)
- The fourth digit can only be the last 2 (i.e. 1 digit)
- The fifth digit can be any of 0 - 9 (i.e. 10 digits)
- The sixth digit can be any of 0 - 9 (i.e. 10 digits)
So, we have:
![Case\ 1 = 3 * 1 * 2 * 1 * 10 * 10](https://tex.z-dn.net/?f=Case%5C%201%20%3D%203%20%2A%201%20%2A%202%20%2A%201%20%2A%2010%20%2A%2010)
![Case\ 1 = 600](https://tex.z-dn.net/?f=Case%5C%201%20%3D%20600)
Case 2: If the sequence starts from the second digit
- The first digit can be any of 1 - 9 (i.e. 9 digits)
- The second digit can be any of the three 2's (i.e. 3 digits)
- The third digit can only be 0
- The fourth digit can be any of the remaining 2's (i.e. 2 digits)
- The fifth digit can only be the last 2 (i.e. 1 digit)
- The last digit can be any of 0 - 9 (i.e. 10 digits)
So, we have:
![Case\ 2 = 9 * 3 * 1 * 2 * 1 * 10](https://tex.z-dn.net/?f=Case%5C%202%20%3D%209%20%2A%203%20%2A%201%20%2A%202%20%2A%201%20%2A%2010)
![Case\ 2 = 540](https://tex.z-dn.net/?f=Case%5C%202%20%3D%20540)
Case 2: If the sequence starts from the third digit
- The first digit can be any of 1 - 9 (i.e. 9 digits)
- The second digit can be any of 0 - 9 (i.e. 10 digits)
- The third digit can be any of the three 2's (i.e. 3 digits)
- The fourth digit can only be 0
- The fifth digit can be any of the remaining 2's (i.e. 2 digits)
- The last digit can only be the last 2 (i.e. 1 digit)
So, we have:
![Case\ 3 = 9 * 10 * 3 * 1 * 2 * 1](https://tex.z-dn.net/?f=Case%5C%203%20%3D%209%20%2A%2010%20%2A%203%20%2A%201%20%2A%202%20%2A%201)
![Case\ 3 = 540](https://tex.z-dn.net/?f=Case%5C%203%20%3D%20540)
The total number of whole numbers is:
![Total = 600 + 540 + 540](https://tex.z-dn.net/?f=Total%20%3D%20600%20%2B%20540%20%2B%20540)
![Total = 1680](https://tex.z-dn.net/?f=Total%20%3D%201680)
Hence, there are 1680 6-digit whole numbers that the digits
Read more about combination and permutation at:
brainly.com/question/2292449
Answer:
3x-4=2x+1 the answer is x=5
3x-4-2x=2x+1-2x the answer is x=5
x-4=1 the answer is x=5
x-4+4=1-4 the answer is x=-3
x=-3 is already the answer
Step-by-step explanation:
3x-4=2x+1
=3x-2x=1+4
=1x=5
=1x/1=5/1
=x=5
3x-4-2x=2x+1-2x
=3x-2x-2x+2x=1+4
=1x=5
=1x/1=5/1
=x=5