Question

(x-3)^2/3=4 where x is a real number. provide an exact answer

Answer 1

I hope this helps you

Answer 2

$\frac{(x-3)^{2}}{3} = 4 \\ (x-3)^{2} = 12 \\ x^{2}-6x+9 = 12 \\ x^{2} -6x-3=0$

The only thing I can think of is using the quadratic formula to solve this one