Guided Practice

Mathematics

1 answer:

Leto [7]4 years ago

8 0

Answer:

yes; y = 1.8x

Step-by-step explanation:

Answer for the question :

Yes, Y varies directly with X, and the equation is :

Y = 1.8X

NOTE : For every value of X, when you multiply them with 1.8, you will get the corresponding Y.

Y = 1.8 x X

5.4 = 1.8 x 3

12.6 = 1.8 x 7

21.6 = 1.8 x 12 (Q.E.D.)

That’s the answer, good luck in solving the question!

:-)

ideal all you ought to do is to divide the y via potential of x and u get the equation working occasion #a million y=32 / x=4 then u have y/x=32/4 ----> y=8x and do the comparable indoors something so #2 y=-20 & x=-20 so y/x=-20/-20 y=x etc

You might be interested in

Revel and Scooters are the best scooter experience in the Nation which is the best scooter rental service in the nation? Create

Luda [366]

Answer:

See the graph with both lines attached

A) From the tables we see the constant change of values in the second column and the initial value is zero.

This represents a proportional relationship for both tables.

B) Revel

Rate of change is 5 per hour, the equation is:
y = 5x, where y is cost, x - is the number of hours

Scooters

Rate of change is 6 per hour, the equation is:
y = 6x, where y is cost, x - is the number of hours

C) When x = 12,

y = 5*12 = $60 for Revel
y = 6*12 = $72 for Scooters

D) The point (4, 24) represents that:

The cost of 4 hours is $24

E) The second table has confusing titles (days and number of cell phones) but if we assume its same as the first table, then Revel has lower rate as 5 < 6.

Comparing the prices and the graph, Revel has better rate per hour.

8 0

3 years ago

A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$