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Stells [14]
3 years ago
9

The ratio of the number of Mary's necklaces to the number of Helen's necklaces is 25:9.Mary's has 100 necklaces. How many neckla

ces does Helen's have.
Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer: 36

Step-by-step explanation:

Given

The ratio of Mary's to Helen's necklaces is 25:9

Mary has 100 necklaces

Suppose Helen has x necklaces

Therefore the ratio can be written like

\Rightarrow \dfrac{25}{9}=\dfrac{100}{x}\\\\\Rightarrow x=\dfrac{100}{25}\times 9\\\\\Rightarrow x=4\times 9\\\Rightarrow x=36

So, Helen has 36 necklaces

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Seven customers enter a clothing store and are observed to determine if they will make a purchase. The store owner states that t
blondinia [14]

Answer: Mean = 5.25

Variance = 1.3125

Standard deviation = 1.456

Step-by-step explanation:

The mean and variance of a binomial distribution with parameters n (number of trials) and p ( the probability of getting success in each trial) is given by :-

\text{Mean}=np\\\\\text{Variance}=np(1-p)

Given : The total number of enter a clothing store : n=7

The probability of a customer making a purchase= 0.75

Now,

\text{Mean}=7(0.75)=5.25\\\\\text{Variance}=7(0.75)(0.25)=1.3125\\\\\Rightarrow\ \text{Standard deviation}=\sqrt{1.3125}=1.14564392374\approx1.1456

3 0
3 years ago
2) The following table presents the probability distribution of the number of vacations X taken last year for a randomly chosen
algol [13]

The mean of the discrete probability distribution is of 1.28.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

Then, considering the given distribution, the mean is given by:

E(X) = 0(0.13) + 1(0.61) + 2(0.15) + 3(0.07) + 4(0.04) = 1.28.

More can be learned about the mean of a discrete probability distribution at brainly.com/question/24855677

3 0
2 years ago
(GIVING BRAINLIEST!!!)
DerKrebs [107]

Answer:

d

Step-by-step explanation:

it is d

4 0
3 years ago
Read 2 more answers
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v&gt;=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
3 years ago
Factor the expression -15t-6
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The only way the expression can be factored is if a -3 is pulled out...

-3(5t+2)
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