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lubasha [3.4K]
3 years ago
5

What is the improper fraction of 20-7

Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

\frac{20}{7}=2\frac{6}{7}

Step-by-step explanation:

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elena55 [62]

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Step-by-step explanation:

oh my 150 overdue

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Which ratio is not equivalent to 12/16 <br> A 3/4<br> B6/8<br> C 8/10<br> D 24/32
arsen [322]

Answer:

8/10

Step-by-step explanation:

8/10=0.8

12/16=0.75

0.8 and 0.75 are the same or they aren't equivalent

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3 years ago
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On a day wilderness expedition you'll need to heat of water to the boiling point each day. The air temperature will average . Yo
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Step-by-step explanation:5 cause i say so

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3 years ago
The volume of Pyramid A is 704 cm3 and the volume of Pyramid B is 297 cm3. If the pyramids are similar and the surface area of P
SIZIF [17.4K]

Answer:

272 cm²

Step-by-step explanation:

Step 1

We have to find the scale factor

When given the volume of two solids, the formula for the scale factor is

V1/V2 = (Scale factor)³

The volume of Pyramid A is 704 cm³ and the volume of Pyramid B is 297 cm³

V1 = Pyramid A

V2 = Pyramid B

704/297 = (scale factor)³

We simplify the left hand side to simplest fraction

The greatest common factor of 704 and 297 = 11

704÷11/297÷11 = (scale factor)³

64/27 = (scale factor)³

We cube root both sides

cube root(scale factor)³ = cube root (64/27)

scale factor = (4/3)

Step 2

(Scale factor)² = S1/S2

S1 = Surface area of Pyramid A =?

S2 = Surface area of Pyramid B = 153 cm²

Hence,

(4/3)² = S1/153

16/9 = S1/153

Cross Multiply

S1 × 9 = 16 × 153

S1 = 16 × 153/9

S1 = 272 cm²

Therefore, the Surface Area of Pyramid A = 272 cm²

4 0
3 years ago
Parallelogram ABCD is dilated to form parallelogram EFGH. Side BC is proportional to side CD. Which corresponding side is propor
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Answer:

It is given that , Parallelogram ABCD is dilated to form parallelogram EFGH.

When Dilation of a geometrical shape takes place, the two→→image and Pre image will be Similar.

Parallelogram ABCD ~ Parallelogram EFGH

Since Similar shapes have , Proportional side Lengths as well as length of their Diagonal will be proportional.

\frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{EH}=\frac{AC}{EG}=\frac{BD}{EG}

So, Segment FG will be proportional to Segment BC.

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