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2 years ago

14

The transfer of thermal energy for a warmer object too a cooler one. 10 points

1 answer:

erica [24]2 years ago

3 0

Answer: The movement of heat from a warmer object to a cooler one is called heat transfer

Explanation:

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Insertion mutation definition ?

blondinia [14]

Answer:

Insertion is a type of mutation involving the addition of genetic material. An insertion mutation can be small, involving a single extra DNA base pair, or large, involving a piece of a chromosome.

Explanation:

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2 years ago

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Moles of Zn(NO3)2 in 131.50g of this substance.

Degger [83]

<span>number of moles= mass / molecular mass
mass=131.50g
molecular mass of Zn(NO3)2 =189.39 g/mol
number of moles = 131.50 g/189.39 g/mol =0.69433 mol</span>

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3 years ago

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The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

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3 years ago

Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. What distance did Jesse travel? 1 m 5 m, northeast 7

boyakko [2]

7.0 meters because 3.0+4.0=7

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2 years ago

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An elephant puts a force of 30,000 N on its four feet,

IceJOKER [234]

Explanation:

pressure is Force/area

30000/0.75

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2 years ago