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faust18 [17]
3 years ago
7

According to Hund's rule, if three electrons are available to fill a set of p orbitals, how will the electrons be arranged? *

Chemistry
1 answer:
forsale [732]3 years ago
4 0
The answer is A
Hund's rule states that electrons are filled singly in each orbital before pairing
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1. Un átomo de volframio (W) tiene 74 protones y 108 neutrones. ¿Cuál es su representación adecuada?
german

Answer:

Iffdldzdosodolzf cvbvxhmnvhihsoszüf

8 0
2 years ago
The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
xxTIMURxx [149]

Answer:

Gallium-72

Explanation:

The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

The mass number is the sum of the protons and the neutrons

In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72

Therefore, the isotope is gallium - 72.

3 0
3 years ago
Which of the following series of isoelectronic ions (Mg²⁺, N³⁻, F⁻, Si⁴⁺) has the ionic radii in order of largest to smallest? A
Rom4ik [11]

Answer:

Option (d) is correct

N³⁻ > F⁻ > Mg²⁺ > Si⁴⁺

Explanation:

Total electrons for all the species = 10

So these are <u>iso electronic</u> with each other.

We know

Ionic radii ∝ \frac{Magnitude of Negative Charge}{Magnitude of Positive Charge}

  • Si⁴⁺ has 14 protons and 10 electrons
  • Mg²⁺ has 12 protons and 10 electrons
  • N³⁻ has 7 protons and 10 electrons
  • F⁻ has 9 protons and 10 electrons
  • Iso electronic species with greatest number of protons have small size and vice versa.
  • So Si⁺⁴ have smallest size and N³⁻ have largest in size
4 0
3 years ago
Binary Covalent (molecular) Compounds
prisoha [69]

Answer:

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Explanation:

5 0
2 years ago
Can someone please help me please?
OleMash [197]
I would say the second option

Hope this helps *smiles*
8 0
3 years ago
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