According to Hund's rule, if three electrons are available to fill a set of p orbitals, how will the electrons be arranged? *

Given that you have 14.5 moles of n2, how many moles of h2 are theoretically needed to produce 30.0 moles of nh3 according to re

erastovalidia [21]

45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

$\large{\boxed{\boxed{\bold{mol=\frac{mass}{molar\:mass}}}}$

Reaction that happens :

N₂ +3H₂ ⇒ 2NH₃

mole N₂ : H₂ : NH₃ = 1 : 3 : 2

To produce 30.0 moles of NH₃,

H₂ needed :

$mole~H_2~=~\frac{3}{2}\times~30~mole$

mole H₂ = 45 mole

N₂ needed :

$mole~N_2~=~\frac{1}{2}~\times~30$

mole N₂ = 15 mole

So the minimum N₂ needed is: 15 mole

14.5 moles of N₂ can only produce NH₃ :

$mole~NH_3~=~\frac{2}{1}~\times~14.5$

mole NH₃ = 29 mole

<h3>Learn more </h3>

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Keywords: mole, NH₃, N₂, H₂

7 0

2 years ago

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Which battle led to the mass displacement of Cherokee from their homes?

zzz [600]

Answer:

option d.......................

3 0

2 years ago

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How would a collapsing universe affect light emitted from clusters and superclusters? A. Light would acquire a blueshift. B. Lig

Lady_Fox [76]

Answer:

Choice A: Light would acquire a blueshift.

Explanation:

When a universe collapses, clusters of stars start to move towards each other. There are two ways to explain why light from these stars will acquire a blueshift.

Stars move toward each other; Frequency increases due to Doppler's Effect.

The time period $t$ of a beam of light is the same as the time between two consecutive peaks. If $\lambda$ is the wavelength of the beam, and both the source and observer are static, the time period $T$ will be the same as the time it takes for light travel the distance of one $\lambda$ (at the speed of light in vacuum, $c$ ).

$\displaystyle t = \frac{\lambda}{c}$ .

Frequency $f$ is the reciprocal of time period. Therefore

$\displaystyle f = \frac{1}{t} = \frac{c}{\lambda}$ .

Light travels in vacuum at a constant speed. However, in a collapsing universe, the star that emit the light keeps moving towards the observer. Let the distance between the star and the observer be $d$ when the star sent the first peak.

Distance from the star when the first peak is sent: $d$ .
Time taken for the first peak to arrive: $\displaystyle t_1 =\frac{d}{c}$ .

The star will emit its second peak after a time of. Meanwhile, the distance between the star and the observer keeps decreasing. Let $v$ be the speed at which the star approaches the observer. The star will travel a distance of $v\cdot t$ before sending the second peak.

Distance from the star when the second peak is sent: $d - v\cdot t$ .
Time taken for the second peak to arrive: $\displaystyle t_2 =t + \frac{d - v\cdot t}{c}$ .

The period of the light is $t$ when emitted from the star. However, the period will appear to be shorter than $t$ for the observer. The time period will appear to be:

$\begin{aligned}\displaystyle t' &= t_2 - t_1\\ &= t + \frac{d - v\cdot t}{c} - \frac{d}{c}\\&= t + (\frac{d}{c} - \frac{v\cdot t}{c}) -\frac{d}{c}\\&= t - \frac{v\cdot t}{c} \end{aligned}$ .

The apparent time period $t'$ is smaller than the initial time period, $t$ . Again, the frequency of a beam of light is inversely proportional to its period. A smaller time period means a higher frequency. Colors at the high-frequency end of the visible spectrum are blue and violet. The color of the beam of light will shift towards the blue end of the spectrum when observed than when emitted. In other words, a collapsing universe will cause a blueshift on light from distant stars.

The Space Fabric Shrinks; Wavelength decreases as the space is compressed.

When the universe collapses, one possibility is that clusters of stars move towards each other. Alternatively, the space fabric might shrink, which will also bring the clusters toward each other.

It takes time for light from a distant cluster to reach an observer on the ground. The space fabric keeps shrinking while the beam of light makes its way through the space. The wavelength of the beam will shrink at the same rate. The wavelength of the beam of light will be shorter by the time the beam arrives at its destination.

Colors at the short-wavelength end of the visible spectrum are blue and violet. Again, the color of the light will shift towards the blue end of the spectrum. The conclusion will be the same: a collapsing universe will cause a blueshift on light from distant stars.

8 0

2 years ago

Given the following UNBALANCED reaction: NH3 (g) <--> N2 (g) + H2 (g) If 1

Yakvenalex [24]

Answer:

C. 1.35

Explanation:

2NH3 (g) <--> N2 (g) + 3H2 (g)

Initial concentration 2.2 mol/0.95L 1.1 mol/0.95L 0

change in concentration 2x x 3x

-0.84 M +0.42M +1.26M

Equilibrium 1.4 mol/0.95L=1.47M 1.58 M 1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0

2 years ago

Help me number 1 pleasw

Vaselesa [24]

The answer to number 1 is D

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3 years ago

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