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NeX [460]
3 years ago
14

What is 3 divided by 1/6?

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

18

Step-by-step explanation:

Rainbow [258]3 years ago
8 0

Answer:

The correct answer is 18

Step-by-step explanation:

HAVE A GOOD DAY!

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In a store, 9/200 of the shirts are pink and 69/600 are orange. What percent of the shirts are not pink or orange?​
pychu [463]

Answer:

84%

Step-by-step explanation:

The percentage of pink shirts

= 9/200 × 100%

= 9/2

= 4.5%

The percentage of orange shirts

= 69/600 × 100%

= 69/6

= 11.5%

The percentage of the shirts which are not pink or orange

= 1 - 4.5% - 11.5%

= 84%

<u>Alternative</u>

Find their common denominator.

9/200

= 9×3 / 200×3

= 27/600

The total percentage of shirts in pink and orange

= (27/600 + 69/600) × 100%

= 96/600 × 100%

= 16%

The percentage of the shirts which are not pink or orange

= 1 - 16%

= 84%

3 0
3 years ago
to download movies off the internet, you must pay 1.99 per movie,plus one time fee of 5.50 write an expression to show the total
Oksanka [162]
1.99x+5.5= total cost
8 0
3 years ago
Read 2 more answers
The dot plots below show the number of points scored by Sam and Daniel in 15 basketball games.
Bas_tet [7]

Answer:

B.

Step-by-step explanation:

Sam median = 12 which has 3 points scored.

Daniel median = 16 which has 3 points scored.

Both scored the same amount of data which is 3 points.

Both the ranges are 16. so it cant be A or C.

3 0
3 years ago
I need the answer to this fast<br> Please
jeyben [28]
The initial function is slope

=> slope = 7-1/6-0 = 6/6 = 1

Hope this helps you :)
5 0
2 years ago
In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne
Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0
3 years ago
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