Answer:
15
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(5+x) * 5 = 10^2
Distribute
25 +5x = 100
Subtract 25 from each side
25-25 +5x = 100-25
5x= 75
Divide by 5
5x/5 = 75/5
x = 15
Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Answer:
13%
Step-by-step explanation:
Its out of 100 people so:
47+33+7 = 87% own a pet
100-87=13%
Answer:
True. See explanation below
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
If we assume that we have
groups and on each group from
we have
individuals on each group we can define the following formulas of variation:
And we have this property
The degrees of freedom for the numerator on this case is given by
where k represent the number of groups.
The degrees of freedom for the denominator on this case is given by
.
And the total degrees of freedom would be
And the we can find the F statistic