In this instance the distance will be the hypotenuse of a right angle triangle.
x = 300/sin30 = 600
They are 600 ft away from each other
Volume sphere A V1 = (4/3)πR³
R=∛((3/4)V1/π)
Volume sphere B V2= (4/3)πr³
r=∛((3/4)V2/π)
R-r = ∛((3/4)40/π) - ∛((3/4)10/π) ≈ 0.8 inch
Answer C. 0.8 inch.
Find the distance between points A-2; 3, B2; 1:
d = √<span>(<span>xb</span> - <span>xa</span>)2 + (<span>yb</span> - <span>ya</span>)2</span> =
= √<span>(2 - (-2))2 + (1 - 3)2</span> =
= √<span>42 + (-2)2</span> = √16 + 4 =
<span>= <span>√20</span><span><span> </span></span></span>
