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Kipish [7]
3 years ago
8

Indica lo que harías en el laboratorio para preparar: 100 mL de una disolución al 2% V/V de etanol.

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

Explanation:

Mide 2mL de etanol, añadelo a un matraz aforado, pon agua hasta llegar a 100mL

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For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when
KATRIN_1 [288]

Answer: Concentration of N₂ is 4.8.10^{9} M.

Explanation: K_{c} is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For

N2(g) + 2 O2(g) ⇄ 2 NO2(g)

K_{c} = \frac{[NO2]^{2} }{[N2][O2]^{2} }

From the question concentration of NO2 is twice of O2:

[NO2] = 2[O2]

Substituting this into K_{c}:

K_{c} = \frac{[2O2]^{2} }{[N2][O2]^{2} }

8.3.10^{-10} = \frac{4O2^{2} }{[N2].O2^{2} }

[N2] = \frac{4O2^{2} }{8.3.10^{-10}.O2^{2}  }

[N2] = \frac{4}{8.3.10^{-10} }

[N2] = 4.8.10^{9}

The concentration of N2 in the equilibrium is [N2] = 4.8.10^{9}M.

6 0
3 years ago
Which best describes the asteroid belt
harina [27]

i think that the answer is d. millions of small rocky objects

5 0
4 years ago
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Will reward brainliest<br> Explain why all arrhenius acids can be considered bronsted lowry acids
GuDViN [60]

Answer:

Explanation:

A bronsted lowry acid just means that it donates a proton.

An arrhenius acid dissolves in water to donate a proton

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3 0
3 years ago
According to the following reaction, how many grams of potassium phosphate will be formed upon the complete reaction of 29.6 gra
Ugo [173]

Answer:

There is 37.36 grams of K3PO4 produced

Explanation:

Step 1: Data given

Mass of H3PO4 = 29.6 grams

KOH is in excess

Molar mass of KOH = 56.11 g/mol

Molar mass of H3PO4 = 97.99 g/mol

Step 2: The balanced equation

3KOH(aq) + H3PO4(aq) ⇔ K3PO4(aq)+3H2O(l)

Step 3: Calculate mass of KOH

Mass KOH = mass KOH / molar mass KOH

Mass KOH = 29.6 grams / 56.11 g/mol

Mass KOH = 0.528 moles

Step 4: Calculate moles of K3PO4

Since KOH is the limiting reactant, We need 3 moles of KOH for each moles of H3PO4, to produce 1 mole of K3PO4 and 3 moles of H2O

For 0.528 moles of KOH we'll have 0.528/3 =  0.176 moles of K3PO4

Step 5: Calculate mass of K3PO4

Mass K3PO4 = moles K3PO4 * molar mass K3PO4

Mass K3PO4 = 0.176 moles * 212.27 g/mol

Mass K3PO4 = 37.36 grams

There is 37.36 grams of K3PO4 produced

8 0
3 years ago
Describe the position of metal ,non metals and metollieds in perodic tables​
siniylev [52]
Non metals and metollids in periodic tables are the same how this helps ;)
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3 years ago
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