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kaheart [24]
2 years ago
10

What is another name for a beta minus (β–) particle?

Chemistry
2 answers:
Vikki [24]2 years ago
5 0

Answer: Another name for beta-minus particle is electron.

Explanation: Beta-minus particle (_{-1}^0\beta ) is released during the beta-minus decay nuclear reaction.

In this nuclear reaction, a neutron gets converted into proton and electron. The electron released is the beta-minus particle.

The charge on these particles is -1 and mass of these particles is negligible.

Delvig [45]2 years ago
4 0
A beta minus particle is an electron.  
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PLZ HELP IM CONFUSED
Marina CMI [18]

Answer:

9.1 mol

Explanation:

The balanced chemical equation of the reaction is:

CO (g) + 2H2 (g) → CH3OH (l)

According to the above balanced equation, 2 moles of hydrogen gas (H2) are needed to produce 1 mole of methanol (CH3OH).

To convert 36.7 g of hydrogen gas to moles, we use the formula;

mole = mass/molar mass

Molar mass of H2 = 2.02g/mol

mole = 36.7/2.02

mole = 18.17mol

This means that if;

2 moles of H2 reacts to produce 1 mole of CH3OH

18.17mol of H2 will react to produce;

18.17 × 1 / 2

= 18.17/2

= 9.085

Approximately to 1 d.p = 9.1 mol of methanol (CH3OH).

6 0
2 years ago
Which of the following bonds is the most polar in nature:
dimaraw [331]
The answer will be (4) HI because the greater the difference of the bonds in electronegativity, the more polar a bond is.
6 0
3 years ago
Which is an unreliable source?
vodomira [7]

Answer:

I believe CDC I s the most reliable

6 0
2 years ago
25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
Paraphin [41]

Answer:

298

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Explanation:

5 0
3 years ago
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A solid powder is known to be a mixture of NaCl and Na2CO3, but the relative amounts of each compound in the sample are unknown.
AveGali [126]

Answer:

Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.

Explanation:

Na_2CO_3(aq) +2 HCl(aq)\rightarrow 2NaCl(aq) + H_2O(l)+CO_2(g)

Molarity of HCl solution = 0.1174 M

Volume of HCl solution = 83.15 mL = 0.08315 L

Moles of HCl = n

molarity=\frac{moles}{Volume (L)}

0.1174 M=\frac{n}{0.08315 L}

n=0.1174 M\times 0.08315 L=0.009762 mol

According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then 0.009762 mol of HCl will recat with:

\frac{1}{2}\times 0.009762 mol=0.004881 mol

Moles of Sodium carbonate = 0.004881 mol

Volume of the sodium carbonate containing solution taken = 1L

Concentration of sodium carbonate in the solution before the addition of HCl:

[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L

4 0
3 years ago
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