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fiasKO [112]
3 years ago
11

Calculate the heat required to convert 52.5 g of c2cl3f3 from a liquid at 11.05 ∘c to a gas at 76.65 ∘c.

Chemistry
1 answer:
Lorico [155]3 years ago
8 0
<span>Answer: We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees) That means we heated it up 36.55 degrees The formula to solve this is C = Q / M x dT where C is the specific heat of the liquid CFC (.91 J/G/C) Q is the amount of heat required (what we're trying to find out) M is the mass (52.5 grams) and dT is the temperature difference (36.55 degrees) Now put in the values and find out what Q is .91 = Q / 52.5 x 36.55 .91 = Q / 1918.875 Q = 1746.17 joules to heat up the liquid CFC</span>
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5 0
3 years ago
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B)
SCORPION-xisa [38]

For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".

<u>Option: C</u>

<u>Explanation:</u>

Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.

Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.

6 0
3 years ago
The rate constant, k, for a first-order reaction is equal to 4.3 × 10-4 s-1. What is the half-life for the reaction? The rate co
pantera1 [17]

Answer:

1.6 × 10³ s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

rate=k \times [A]^{m}

where,

rate is the reaction rate

k is the rate constant

[A] is the molar concentration of the reactant A

m is the reaction order

When m = 1, we have a first-order reaction. We can calculate the half-life for this reaction using the following expression.

t_{1/2}=\frac{ln2}{k} =\frac{ln2}{4.3 \times 10^{-4}s^{-1} }=1.6 \times 10^{3}s

4 0
3 years ago
A student needs to prepare 100. mL of 0.612 M Cu(NO3)2 solution. What mass, in grams, of copper(II) nitrate should the student u
Temka [501]

Answer: 11.5 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution

Molarity=\frac{n\times 1000}{V_s}

where,

Morality = 0.612 M

n= moles of solute  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

0.612=\frac{n\times 1000}{100ml}

n=0.0612moles

Mass={\text {moles of solute }}{\times {\text {molar mass}}=0.0612moles\times 187.56g/mol=11.5g

Therefore, the mass of copper (II)nitrate required is 11.5 grams

3 0
3 years ago
Water has a density of 1g/ml. what is the mass of the water if it fills a 10ml container?
notka56 [123]
It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
8 0
2 years ago
Read 2 more answers
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