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fiasKO [112]
3 years ago
11

Calculate the heat required to convert 52.5 g of c2cl3f3 from a liquid at 11.05 ∘c to a gas at 76.65 ∘c.

Chemistry
1 answer:
Lorico [155]3 years ago
8 0
<span>Answer: We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees) That means we heated it up 36.55 degrees The formula to solve this is C = Q / M x dT where C is the specific heat of the liquid CFC (.91 J/G/C) Q is the amount of heat required (what we're trying to find out) M is the mass (52.5 grams) and dT is the temperature difference (36.55 degrees) Now put in the values and find out what Q is .91 = Q / 52.5 x 36.55 .91 = Q / 1918.875 Q = 1746.17 joules to heat up the liquid CFC</span>
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A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. What was its acceleration?
Zigmanuir [339]

Acceleration is defined as velocity per unit time.

Acceleration=\frac{Velocity}{time}

a=\frac{dv}{dt}

Here, a=acceleartion,

v=velocity=36 m/s

t=time=12 s

a=\frac{dv}{dt}

a=\frac{36}{12}

a=3 ms⁻²

A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. So acceleration that is a=3 ms⁻².


4 0
3 years ago
Read 2 more answers
In Keynes's liquidity preference framework, as the expected return on bonds increases (holding everything else unchanged), the e
Julli [10]

Answer:

the correct words to fill up the blank spaces are falls and money

Explanation:

.1. the expected return on money falls

.2. causing the demand for money to fall.

3 0
3 years ago
A sample of argon gas has a volume of 73 mL at a pressure of 1.20 atm and a temperature of 112 degrees Celsius. What is the fina
NeX [460]

Answer:

V₂ → 106.6 mL

Explanation:

We apply the Ideal Gases Law to solve the problem. For the two situations:

P . V = n . R . T

Moles are still the same so → P. V / R. T = n

As R is a constant, the formula to solve this is: P . V / T

P₁ . V₁ / T₁ = P₂ .V₂ / T₂   Let's replace data:

(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C

((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂

58.66 mL.atm = 0.55 atm . V₂

58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL

3 0
3 years ago
How many moles are in 20 grams of Ar?​
pashok25 [27]

Answer:

moles Ar in 20g = 0.500 mole Ar

Explanation:

moles = grams given / formula weight = 20g / 39.948g·mol⁻¹ = 0.500 mole Ar

7 0
3 years ago
What is the density of a solid that has a mass of 9.2 grams and a volume of 12.3 cm3 ? Would this object float or sink in water?
cluponka [151]
  • Mass=9.2g
  • Volume=12.3

\boxed{\sf Density=\dfrac{Mass}{Volume}}

\\ \sf\longmapsto Density=\dfrac{9.2}{12.3}

\\ \sf\longmapsto Density=0.74g/cm^3

  • Density of water =1g/cm^3

It will float in water

7 0
3 years ago
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