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3 years ago

Calculate the heat required to convert 52.5 g of c2cl3f3 from a liquid at 11.05 ∘c to a gas at 76.65 ∘c.

1 answer:

8 0

<span>Answer: We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees) That means we heated it up 36.55 degrees The formula to solve this is C = Q / M x dT where C is the specific heat of the liquid CFC (.91 J/G/C) Q is the amount of heat required (what we're trying to find out) M is the mass (52.5 grams) and dT is the temperature difference (36.55 degrees) Now put in the values and find out what Q is .91 = Q / 52.5 x 36.55 .91 = Q / 1918.875 Q = 1746.17 joules to heat up the liquid CFC</span>

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In redox reactions, _____________ occurs when electrons are lost by a molecule. ______________ occurs when electrons are gained

madam [21]

Answer:

Oxidation, Reduction

Explanation:

A redox reaction is a short form for reduction-oxidation.

Reduction is a term which means that electron is gained while oxidation is a term which means that electron Is lost.

The species that gain electron is known as the oxidizing agent while the species losing electrons is known as the reducing agent

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2 years ago

what is the concentration in ppm of a solution which is prepared by dissolving in 15mg of nacl in 200ml water

bezimeni [28]

Answer:

Explanation:

In weight/volume (w/v) terms,

1 ppm = 1g m-3 = 1 mg L-1 = 1 μg mL-1

200 mL = 0.2 L

15 / 0.2 mg L-1 =75 ppm

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2 years ago

The process invented in 1864 to reduce the amount of bacteria in liquids and foods by heating them to high temperatures is calle

dlinn [17]

The key is a process called <span>pasteurization</span>

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3 years ago

How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?

Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

$Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}$

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

$\frac{3}{2} \times 5.3 mol\\= 7.95 mol$

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

$No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g$

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

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2 years ago

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Ne4ueva [31]

Answer:

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Explanation:

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2 years ago