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fiasKO [112]
3 years ago
11

Calculate the heat required to convert 52.5 g of c2cl3f3 from a liquid at 11.05 ∘c to a gas at 76.65 ∘c.

Chemistry
1 answer:
Lorico [155]3 years ago
8 0
<span>Answer: We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees) That means we heated it up 36.55 degrees The formula to solve this is C = Q / M x dT where C is the specific heat of the liquid CFC (.91 J/G/C) Q is the amount of heat required (what we're trying to find out) M is the mass (52.5 grams) and dT is the temperature difference (36.55 degrees) Now put in the values and find out what Q is .91 = Q / 52.5 x 36.55 .91 = Q / 1918.875 Q = 1746.17 joules to heat up the liquid CFC</span>
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I believe that the answer is A, continental-continental.
7 0
3 years ago
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What is the kinetic energy of a 5 kg object moving at 7 m/s?
valina [46]

Answer:

122.5 Joule, or 122.5 j

Explanation:

Given,

mass of the object (m) = 5 kg

velocity of the object (v) = 7 m/s

Kinetic energy = \frac{1}{2} × m × v²

Applying the formula:

Kinetic energy = \frac{1}{2} × 5 × 7²

⇒ \frac{1}{2} × 5 × 7 × 7

⇒ \frac{245}{2}

⇒ 122.5 Joule, or 122.5 j

Kinetic energy is the energy that an object gains as the result of the motion.  It also depends on the mass of the object and force with which the motion is applied.  In the given question, the mass of the object is 5 kg and the force of the velocity by which it is moving is 7 m/s.

3 0
3 years ago
Kc for the reaction N2O4 &lt;=&gt; 2NO2 is 0.619 at 45 degrees C If 50.0g of N2O4 is introduced into an empty 2.10L container, w
Nadya [2.5K]

Answer:

p(N2O4) = 0.318 atm

p(NO2) = 7.17 atm

Explanation:

Step 1: Data given

Kc = 0.619

Temperature = 45.0 °C

Mass of N2O4 = 50.0 grams

Volume = 2.10 L

Molar mass N2O4 = 92.01 g/mol

Step 2: The balanced equation

N2O4 ⇔ 2NO2

Step 3: Calculate moles N2O4

Moles N2O4 = 50.0 grams / 92.01 g/mol

Moles N2O4 = 0.543 moles

Step 4: The initial concentration

[N2O4] = 0.543 moles/2.10 L = 0.259 M

[NO2]= 0 M

Step 5: Calculate concentration at the equilibrium

For 1 mol N2O4 we'll have 2 moles NO2

[N2O4] = (0.259 -x)M

[NO2]= 2x

Step 6: Calculate Kc

Kc = 0.619=  [NO2]² / [N2O4]

0.619 = (2x)² / (0.259-x)

0.619 = 4x² / (0.259 -x)

x = 0.1373  

Step 7: Calculate concentrations

[N2O4] = (0.259 -x)M = 0.1217 M

[NO2]= 2x = 0.2746 M

Step 8: The moles

Moles = molarity * volume

Moles N2O4 = 0.1217 M * 2.10  = 0.0256 moles

Moles NO2 = 0.2746 M * 2.10 = 0.577 moles

Step 9: Calculate partial pressure

p*V = n*R*T

⇒ with p = the partial pressure

⇒ with V = the volume = 2.10 L

⇒ with n = the number of moles

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature = 45 °C = 318 K

p = (nRT)/V

p(N2O4) = (0.0256 *0.08206 * 318)/ 2.10

p(N2O4) = 0.318 atm

p(NO2) = (0.577 *0.08206 * 318)/ 2.10

p(NO2) = 7.17 atm

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3 years ago
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Ronch [10]

Answer:

43.7

Explanation:

mole is equal mass concentration/ moler mass of MgCl²

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