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mixer [17]
3 years ago
6

Free 100 plus Brainliest to the first person

Mathematics
2 answers:
Ivanshal [37]3 years ago
5 0

Answer:

thank you!!

Step-by-step explanation:

sesenic [268]3 years ago
4 0

Answer:

Thanks man really appreciate it

Step-by-step explanation:

Have a great day

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the lowest point in the Pacific Ocean is about - 11,000 meters. The lowest point in the Atlantic Ocean is about - 8,000 meters.
Ugo [173]
The Pacific Ocean has the lowest point, by 3000 meters
3 0
3 years ago
Using the function g(x) = -2x + 5, what would the input need to be for an output of -5?
vivado [14]

Answer:

it would be -5

Step-by-step explanation:

7 0
3 years ago
If you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows, the tot
ss7ja [257]
The answer is a 
because you would add 12 to x x being the bag
5 0
3 years ago
2 2/5 in kilometers in 3 3/4 minutes unit rate
Mars2501 [29]

Answer:

Step-by-step explanation:

d = r * t     Divide both sides by t

r = d / t

d = distance = 2.25 km

t = time = 3 3/4 minutes = 3.75 minutes

r = 2.25 / 3.75

r = 0.6 km / minute

r = 3/5 km / minute

If the units are different than those given, please state them underneath my answer. I'll get to it as soon as I see your comment.

5 0
3 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
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