<h2>Alex accidentally forgot to stock up on toilet paper before the stay-at-home order. Now he has to buy toilet paper on the black market. Though the price of toilet paper on the black market has mostly stabilized, it still varies from day to day. The daily price of a generic brand 12-pack, X, and the daily price of a generic brand 6-pack, Y, (in rubles) jointly follow a bivariate normal distribution with:
</h2><h2>μx = 2,470, σx = 30, μy = 1,250, σ = 25, p = 0.60.
</h2><h2>(a) What is the probability that 2 (two) 6-packs cost more than 1 (one) 12-pack? (b) To ensure that he will not be without toilet paper ever again, Alex buys 7 (seven) 12-packs and 18 (eighteen) 6-packs. What is the probability that he paid more than 40,000 rubles?
</h2><h2>(c) Suppose that today's price of a 12-pack is 2,460 rubles. What is the probability that a 6-pack costs less than 1,234 rubles today? [1 US dollar is approximately 75 rubles ]</h2>
Wish i could help you don’t have a lot of information
Answer:
sorry I don't know sis ☹️
Answer:
Table 1
Step-by-step explanation:
Constant of proportionality is simply the ratio of y to x. In each of the given tables, the second column is y and the first is x.
Table 1:
4 32/5
10 16
11 88/5
Let's find the constant of proportionality for each row:
R1: (32/5) / 4 = 8/5
R2: 16/10 = 8/5
R3: (88/5) / 11 = 8/5
Thus, since this matches the requirements and all three rows have the same constant, Table 1 is the answer.
If you check the other two tables in the same way, you'll see that neither has a constant of proportionality of 8/5.
Hope this helps!
