A 50mf capacitor, a 0.3H inductor and an 80 ohm resistor is connected in series with a 120v, 60Hz power source
1 answer:
Answer:
Z = 138.5 Ω
Explanation:
In a series RLC circuit the impedance is
Z =
the capacitive impedance is
X_C = 1 / wC
the inductive impedance is
X_L = wL
in this exercise indicate that C = 50 10⁻³ F, L = 0.3 H and the frequency is f=60 Hz
angular velocity and frequency are related
w = 2π f
w = 2π 60
w = 376.99 rad / s
let's calculate
Z =
Z =
Z = √19179.6
Z = 138.5 Ω
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Explanation:
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using equation of
where v=final velocity
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a=acceleration
s=displacement
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negative sign indicates it is deceleration
In order for the object not to slip, the component of the weight parallel to the surface must be equal to the frictional force (which acts in the opposite direction):
The parallel component of the weight is:
where m is the object mass and
is the angle of the inclined plane.
The frictional force is
where
is the coefficient of static friction.
Equalizing the two forces, we have
from which we find
and so, in our problem the coefficient of static friction must be
The parallel component of the weight is:
where m is the object mass and
The frictional force is
where
Equalizing the two forces, we have
from which we find
and so, in our problem the coefficient of static friction must be
Answer:
Y = 40.94m
Explanation:
The initial speed of the sandbag is the same as the balloon and so is its position, so:
Replacing these values:
Yo = 40m Vo = 5m/s g = 9.81m/s^2 t = 0.25s
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Y = 40.94m