Answer:
The force applied to the surface is 9 kilo Newton.
Explanation:
While jumping on the surface the player applies the force that is equal to its weight on the surface.
The mass of the player is given as 90 kg.
Force applied by the player = weight of the player
Force applied by the player = m × g
Where m is the mass of the player and g is acceleration due to gravity
Force applied by the player = 90 × 9.8
Force applied by the player = 882 Newton
Expressing your answer to one significant figure, we get
Force applied by the player =0. 9 kilo Newton
The force applied to the surface is 0.9 kilo Newton.
Answer:
The transverse wave will travel with a speed of 25.5 m/s along the cable.
Explanation:
let T = 2.96×10^4 N be the tension in in the steel cable, ρ = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.
then, if V is the volume of the cable:
ρ = m/V
m = ρ×V
but V = A×L , where L is the length of the cable.
m = ρ×(A×L)
m/L = ρ×A
then the speed of the wave in the cable is given by:
v = √(T×L/m)
= √(T/A×ρ)
= √[2.96×10^4/(4.49×10^-3×7860)]
= 25.5 m/s
Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.
Answer:
15193.62 m/s
Explanation:
t = Time taken = 6.5 hours
u = Initial velocity = 0 (Assumed)
m = Mass of rocket = 1380 kg
F = Thrust force = 896 N
v = Final velocity
a = Acceleration of the rocket
Force

Equation of motion

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s
Answer:
r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.
Explanation:
From a sum of forces:
where Ff = μ * N and 
N - m*g = 0 So, N = m*g. Replacing everything on the original equation:
(eq2)
Solving for r:

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.
Answer:
You could put over six planets the size of Mars inside the Earth. The largest planet in our Solar System, Jupiter's size is astounding. Jupiter has a volume of 1.43 x 1015 cubic kilometers. To show what this number means, you could fit 1321 Earths inside of Jupiter
Explanation: