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Usimov [2.4K]
3 years ago
10

How many electrons are located in the outermost energy level in the Bohr model of a boron atom? hint it not 4

Chemistry
1 answer:
borishaifa [10]3 years ago
6 0
2 is the answer iam not sure about it
Yes
You might be interested in
Assume that a milliliter of water contains 20 drops. How long, in hours, will it take you to count the number of drops
garri49 [273]

Answer:

126.18 hr

Explanation:

Data given:

1 mL of water = 20 drops

count rate = 10 drops/s

time in hours for one gallon = ?

Solution:

First we calculate number of mL (milliliter) of water in gallon

As we know

1 gallon = 3785.4 mL

As,

1 galon consist of 3785.4 mL of water, so now we count number of drops that contain 3785.4 mL of water

As we Know 1 mL water contain 20 drops then 3785.4 mL of water contain how many drops:

Apply unity formula

                    1 mL water ≅ 20 drops

                    3785.4 mL water ≅ X drops

Do cross multiplication

                 X drops of water = 20 drops x 3785.4 mL / 1 mL

                 X drops of water = 75708 drops

So, we come to know that one gallon contain 75708 drops of water and we have to calculate the time in hour to count these drops

First we calculate time in seconds

As we Know 10 drops water count in one second then how many seconds it will take to count 75708 drops

Apply unity formula

                    1 second ≅ 10 drops

                    X second ≅ 75708 drops

Do cross multiplication

                 X second  = 1 second x 75708 drops / 10 drops

                 X second = 7570.8 second

So it take 7570.8 second to count 1 gallon water drops

Now convert seconds to hours

As,

60 seconds = 1 hr

7570.8 second  =  7570.8 / 60 = 126.18 hr

So it take 126.18 hr to count 1 gallon water drops.

6 0
4 years ago
Add a temperature of -33.0 Celsius a sample of a confirmed gas eggs or to pressure of 0.5 to 6 ATM if it's volume remains consta
Levart [38]

<u>Answer:</u> The final temperature of the gas is -220.6°C

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6atm\\T_1=-33^oC=[273-33]K=240K\\P_2=1.31atm\\T_2=?

Putting values in above equation, we get:

\frac{6atm}{240K}=\frac{1.31atm}{T_2}\\\\T_2=\frac{1.31\times 240}{6}=52.4K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

52.4=T(^oC)+273\\\\T(^oC)=-220.6^oC

Hence, the final temperature of the gas is -220.6°C

3 0
4 years ago
Transferring charge by touching or rubbing is called-
mina [271]

Answer:

A) Charging by contact

Explanation:

Transfer of heat by direct contact, Heat energy is conducted from the hotter medium to the cooler medium

3 0
3 years ago
Plz help... answer this question!
Mkey [24]

Answer:

B

Explanation:

Because element is made up of only one type of atoms and figure b show only one type of atoms.

5 0
3 years ago
En condiciones normales 1g de aire ocupa un volumen de 773 mL ¿ qué volumen ocupará la misma masa de aire a 0 ºC y la presión a
emmainna [20.7K]

Answer:

El volumen que ocupará la misma masa de aire es 839.49 mL.

Explanation:

Las condiciones normales de presión y temperatura (abreviado CNPT) o presión y temperatura normales (abreviado PTN o TPN), son términos que implican que la temperatura referenciada es de 0ºC (273,15 K) y la presión de 1 atm (definida como 101.325 Pa).

La ley de Boyle dice que “El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”  y se matemáticamente como

Presión*Volumen=constante

o P*V=k

La ley de Charles es una ley que dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T} =k

La ley de Gay-Lussac​ establece que la presión de un volumen fijo de un gas, es directamente proporcional a su temperatura. Se expresa matemáticamente como:

\frac{P}{T} =k

Combinando estas tres leyes se obtiene:

\frac{P*V}{T} =k

Siendo un estado inicial 1 y un estado final 2, la expresión anterior queda determinada como:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

En este caso:

  • P1=  101325 Pa
  • V1= 773 mL
  • T1= 273.15 K
  • P2= 93,3 kPa= 93300 Pa
  • V2= ?
  • T2= 0°C= 273.15 K

Reemplazando:

\frac{101325 Pa*773 mL}{273,15 K} =\frac{93300 Pa*V2}{273.15 K}

y resolviendo obtenes:

V2=\frac{273.15 K}{93300 Pa} *\frac{101325 Pa*773 mL}{273,15 K}

V2= 839,49 mL

<u><em>El volumen que ocupará la misma masa de aire es 839.49 mL.</em></u>

8 0
3 years ago
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