A =(b x h)/2
= 10 x 8
= 80/2
= 40 mm square
Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
Solution:
- (x² + x – 12)(x² + 10x + 25)
- => (x⁴ + 10x³ + 25x²) + (x³ + 10x² + 25x) + (-12x² - 120x - 300)
- => x⁴ + 10x³ + 25x² + x³ + 10x² + 25x - 12x² - 120x - 300
- => x⁴ + (10x³ + x³) + (25x² + 10x² - 12x²) + (25x - 120x) - 300
- => x⁴ + (11x³) + (23x²) + (-95x) - 300
- => x⁴ + 11x³ + 23x² - 95x - 300
The only term that has a x-variable is "-95x".
The coefficient of x is -95.
23 lines × 5 trees= 115 tree. or. 5 lines × 23 trees = 115 trees
Answer:
12 : 4.92
Step-by-step explanation:
a= apples
12a=4.92
12 : 4.92
