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never [62]
3 years ago
5

Bones and cartilage are connective tissues’ prove this with evidences.

Biology
1 answer:
kherson [118]3 years ago
6 0

Answer:

hope it helps : )

Explanation:

Cartilage and Bone are specialized forms of connective tissue.

They are both made up of cells embedded in an extracellular matrix.

It is the nature of the matrix that defines the properties of these connective tissues.

Cartilage is thin, avascular, flexible and resistant to compressive forces.

Bone is highly vascularized, and its calcified matrix makes it very strong.

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The shape of the cell changes in_______
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Explanation:

Shape change from normal elongated egg-shape to round-shape in stressful environment. These shape changes attain two transition phases. The I-transition phase is reversible where the organism can return to normal if favourable environment persists.

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If u know the water cycle please answer this question
Ksju [112]

Answer:

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6 0
3 years ago
The human MN blood type is determined by two codominant alleles, L(M) and L(N). The frequency of L(M) in Eskimos on a small Arct
tatiyna

Answer:

(a) Frequency of M = 0.64

    Frequency of N = 0.04

    Frequency of MN= 0.32

(b)  Expected frequencies of M = 0.648

     Expected frequencies of MN = 0.304

     Expected frequencies of N =  0.048

Explanation:

(a) If random mating takes place in the population, then  the expected frequencies are

f(L(M)) = p = 0.8

F(L(N)) = q

q= 1 - p

= 1 - 0.8

= 0.2

Frequency of M = p^2 = ( 0.8)^2 = 0.64

Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04

Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32

(b)

F = inbreeding coefficient = 0.05

f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648

f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304

f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048

5 0
3 years ago
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