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Murljashka [212]
3 years ago
10

PLS HELP !!! i’ll give you 15 points

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

A reflection over the x-axis since it horizontal

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Which of the following choices shows the equation solved for y
katen-ka-za [31]

Answer:

#1; y = -\frac{7}{2}x+5

Step-by-step explanation:

7x+2y=10

2y = -7x + 10

\frac{2y}{2} = -\frac{7x}{2} + \frac{10}{2}

y = -\frac{7}{2}x + 5

8 0
3 years ago
Danny invests $10,000 in a savings account that pays 3.5% simple interest. If Danny does not make any additional deposits or wit
SashulF [63]

Answer:

Danny will have 12,450 in his savings account

Step-by-step explanation:

P is the principal amount, $10000.00.

r is the interest rate, 3.5% per year, or in decimal form, 3.5/100=0.035.

t is the time involved, 7....year(s) time periods.

So, t is 7....year time periods.

To find the simple interest, we multiply 10000 × 0.035 × 7 to get that:

The interest is: $2450.00

10000.00 + 2450.00 = 12450.00.

5 0
3 years ago
Read 2 more answers
Miles recorded his height, in inches, from age 10 to age 18, as shown in the table. Age, x 10 11 12 13 14 15 16 17 18 Height, y
RoseWind [281]

Answer: Y=10.76 √(x-9.12)+43.64

Step-by-step explanation:

4 0
3 years ago
What does the middle term have to be in this trinomial to make it a perfect square? <br><br> x^2+?+4
arlik [135]

Answer: 4x

Step-by-step explanation:

Formula: a^2+2ab+b^2.

So in this case our a^2 is x^2. our b^2 is 4.

To find the middle term (2ab) we do 2*x*2 = 4x

5 0
3 years ago
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Suppose your waiting time for a bus in the morning is uniformly distributed on [0, 8], whereas waiting time in the evening is un
ycow [4]

Answer:

41/3

Step-by-step explanation:

given that your waiting time for a bus in the morning is uniformly distributed on [0, 8], whereas waiting time in the evening is uniformly distributed on [0, 10] independent of morning waiting time.

Sum of both waiting times = X+Y

Where X = morning wait time is U(0.8) and

Y = evening wait time is U(0,10)

Since X and Y are independent

Var(x+y) = Var(x)+Var(y)

Var(x) = \frac{8^2-0^2}{12} \\=\frac{16}{3}

Var(Y) = \frac{10^2-0^2}{12} \\=\frac{25}{3}

Var(x+y) \frac{16+25}{3} \\=\frac{41}{3}

5 0
4 years ago
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