The perimeter "P" is equal to the length of the base of one triangle multiplied by the "n" number of triangles in the figure plus two times the length of another side. The equation for the perimeter is P = 5n + 14.
We are given triangles. The triangles are arranged in a certain pattern. The length of the base of each triangle is equal to 5 units. The length of the other two sides is 7 units each. We conclude that all the triangles are isosceles. We need to find the relationship between the number of triangles and the perimeter of the figure. Let the perimeter of the figure having "n" number of triangles be represented by the variable "P".
P(1) = 14 + 5(1)
P(2) = 14 + 5(2)
P(3) = 14 + 5(3)
We can see and continue the pattern. The relationship between the perimeter and the number of triangles is given below.
P(n) = 14 + 5n
To learn more about perimeter, visit :
brainly.com/question/6465134
#SPJ1
f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
Sin ( theta ) = opposite / hypotenuse
sin ( 37° ) = 13 / x
1. Draw the points in the coordinate axes, as in the attached picture.
2. AB and CD are parallel, (both are parallel to the x-axis)
3. A is closer to the y axis than D and C is closer to the C closer than B
4. So combining 2 and 3, we conclude that ABCD is a trapezoid.
5. The remaining thing to check is whether the trapezoid is isosceles or not. For this we drop the heights to AB from points C and D,
and see that the distances from the feets of these heights to the points A and B are not equal.
Answer: Trapezoid