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3 years ago

Please PLEASE HELP ASAP EVERYONE KEEPS PUTTING ABSURD STUFF PLEASEE

Mathematics

1 answer:

levacccp [35]3 years ago

3 0

domain 100 is the answer

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Which of the following statements are always true?

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Answer: A trapezoid is always a parallelogram.

Step-by-step explanation:

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Find the coordinates of the midpoint M and the distance between P(-6, -1) and Q(1,2). Round to the nearest

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Answer:

8.0

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3 years ago

HELP PLEASEE<br> I’m stuck

Sever21 [200]

Answer:

:-):-)

Step-by-step explanation:

1) p<1000

2)p>500

3)By combining the above two, we get: 500<p<1000

Andre will agree as he thinks that the no. of paper clips in the box is less than 1000. But lin will not as she thinks that the no. of clips is more than 500.

4)This time, they both will agree as the no. of paper clips is more than 500 but less than 1000.

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Prove the identity with rules<br> (1-cos(-x)) / (sec(-x)-1) =cosx

Aloiza [94]

By using the rules:

$cos(-x) = cos(x)\\\\sec(x) = \frac{1}{cos(x)}$

We have proven the identity. Below you can follow the demonstration.

<h3></h3><h3>How to prove the identity?</h3>

Here you need to remember two things:

$cos(-x) = cos(x)\\\\sec(x) = \frac{1}{cos(x)}$

Here we have the expression:

$\frac{1 - cos(-x)}{sec(-x) - 1}$

By using the first rule, we can rewrite:

$\frac{1 - cos(-x)}{sec(-x) - 1} = \frac{1 - cos(x)}{sec(x) - 1}$

By using the second rule, we can rewrite:

$\frac{1 - cos(x)}{sec(x) - 1} = \frac{1 - cos(x)}{\frac{1}{cos(x)} - 1}$

Now if we multiply and divide by cos(x), we get:

$\frac{1 - cos(x)}{\frac{1}{cos(x)} - 1} = \frac{1 - cos(x)}{\frac{1}{cos(x)} - 1} *\frac{cos(x)}{cos(x) } = \frac{(1- cos(x))*cos(x)}{1 - cos(x)} = cos(x)$