The 10-kg lamp is suspended from the
1 answer:
Answer:
hello your question is incomplete attached below is the complete diagram
answer : 519 mm
Explanation:
Given the conditions it can be said that the cords are symmetric i.e. AD, BD , CD has same value
hence ; DA = DB = DC = 600 mm
Tension in all cords are the same ( T ) = 50 N
lets assume the angle between the cords and the Z-axis is ∅
∑ Fz = 0
3 * T cos ∅ - 10*9.81 = 0
therefore ; ∅ = 49.16°
looking at attached triangle AD0
tan ∅ =
Hence ; s = 519 mm
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Answer:
Explanation:
given data
Load P = 35 kN
Width of bar W = 50.8 mm
Breadth of bar B = 25 mm
Ratio of crack length to width α = a/W = 0.2
solution
we get here KI for a rectangular bar that is express as
................................1
here Y is the geometrical function
so
Y =
Y =
Y =
Y = 0.9878
so put here value in equation 1
= 5210.45 × 10³
= 5.21 MPa