Answer:
Pressure =
Explanation:
The pressure is calculated by Bernoulli's equation.
Solving it for P2
Now inserting values
P1 = 0 as it is given that initial point is at atmospheric point.
d= density = 2.05 sl/ft3
Vi = 200 mph = 293.33 ft/s
Vf = 273 mph = 400.4 ft/s
Putting these values
Changing the units to pounds per square foot
Answer:
the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm
Explanation:
Given the data in the question;
yield strength σ = 690 Mpa
plane strain fracture toughness K = 32 MPa-
minimum component thickness for which the condition of plane strain is valid = ?
Now, for plane strain conditions, the minimum thickness required is expressed as;
t ≥ 2.5( K / σ
)²
so we substitute our values into the formula
t ≥ 2.5( 32 / 690 )²
t ≥ 2.5( 0.0463768 )²
t ≥ 2.5 × 0.0021508
t ≥ 0.005377 m or 5.38 mm
Therefore, the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm