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2 years ago

For every $2 Joe earns, Michelle earns $3. If Joe

Mathematics

2 answers:

-Dominant- [34]2 years ago

6 0

2x6=12

So all you have to do is multiply 3x6 which equals 18 so your answer is 3x6=18 hope I helped. :)

anyanavicka [17]2 years ago

5 0

Answer:

Step-by-step explanation:

You are going to use The cross multiplication method

$2-------- $12

$3-------- X

X= 12*3=36

36/2=18

Michelle earned $18

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Luci Lulu opened a cookie store in the mall. She found that the relationship between the price of a cookie, p, and the number of

bekas [8.4K]

Answer:

The maximum revenue Luci Lulu can make selling cookies in one day is $2,000.

The price Luci Lulu should sell the cookies to make the maximum revenue is $1.

Step-by-step explanation:

From the question, we have:

x = −2000p + 4000 ..................... (1)

Where;

x = number of cookies sold

p = price of a cookie, p, and the

Revenue function (R) can therefore be obtained as follows:

R = px ……………………….. (2)

If we substitute equation (1) into (2), we will have:

R = p(−2000p + 4000)

R = −2000p^2 + 4000p ……………… (3)

Differentiating equation (3) with respect to p and set it equal to zero, we have:

−4000p + 4000 = 0

Solving for p, we have:

4000 = 4000p

p = 4000 / 4000

p = 1

Therefore, this implies the price Luci Lulu should sell the cookies to make the maximum revenue is $1.

Substituting p = 1 into equation (3), we have:

R = (−2000 * 1^2) + (4000 * 1)

R = (−2000 * 1) + (4000 * 1)

R = −2000 + 4000

R = 2000

This implies that the maximum revenue Luci Lulu can make selling cookies in one day is $2,000.

6 0

3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

2 years ago

Heidi buys shirts for $20 and resells for $24. What is the percentage of Heidi's markup? Plz help me!!

Vadim26 [7]

20% because 4 dollars is 1/5 of 20

8 0

3 years ago

What percentage of tickets sold were to seniors?

Kay [80]

Given:

The number of tickets sold to children $=35+87+62=184.$

The number of tickets sold to adults $=56+177+205=438.$

The number of tickets sold to seniors $=32+14+54=100.$

To determine the percentage of tickets sold to seniors we need to determine the total number of tickets sold to each category.

To determine the percentage of tickets sold to seniors:

In order to determine the percentage of tickets sold to the seniors, we divide the tickets sold to seniors by the total number of tickets sold to children, adults, and seniors.

This value is multiplied with 100 to convert it into a percentage.

The number of tickets sold to seniors $=100.$

The total number of tickets sold to children, adults, and seniors $= 184+438+100=722.$

The percentage of tickets sold to seniors $= \frac{100}{722} (100) = 0.1385(100)=13.85\%.$

Rounding this off, we get the value as 13.9%

Hence, option 1 is the correct answer.

8 0

3 years ago

traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12mph and the total trip took

spayn [35]

Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11( s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.

7 0

3 years ago