Question

When a cup of coffee at 100 degree Celsius cools down ,it loses 12%of its current temperature

Answer 1

Answer:

Temperature after 10 minute = 27.9 degree Celsius

Step-by-step explanation:

Current temperature, P = 100 degree Celsius

% rate in temperature loses = 12% per minute = 0.12

Time,  t = 10 minutes

Temperature after t minutes ,

                                           $= P ( 1 - r )^t\\\\=100( 1 - 0.12)^10\\\\=100(0.278500976)\\\\=27.85$

                                           = 27.9 degree Celsius