All categories

3 years ago

Simplify the expression 5(z+6)=

Mathematics

2 answers:

Lena [83]3 years ago

5 0

5z+30 thats the answer

Effectus [21]3 years ago

3 0

5(z+30) is the answer

You might be interested in

Solve 3 -x = 243 -5 1/5 5

Paraphin [41]

Answer:

$x=-243$

Step-by-step explanation:

The equation is

$-3^{-5}=\frac{1}{x}$

Solve for x

we know that

$-3^{-5}=-\frac{1}{3^{5}}=-\frac{1}{243}$

substitute

$-\frac{1}{243}=\frac{1}{x}$

$x=-243$

3 0

3 years ago

Read 2 more answers

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

3 years ago

Plz help me plz!!!!!!

Mice21 [21]

Answer:

6. was Narbada alienated ...?

7. did Pratima make ...?

8. did Zayasha wander ...?

9. Did Sachin behave as if...?

10. did susan look ...?

12. do <u>sarina and sazina</u> jump ...? (plural noun)

13. Were ... and ... aghast to...?

Step-by-step explanation:

yes/ no question:

Past simple: Did + S + V-bare...?

Passive voice (Past simple): Was/ Were + S + V3/ed (<em>past participle</em>)

4 0

2 years ago

Tom has three times as many action figures as Jerry. If Tom has 27 action figures, how many does Jerry have?

weeeeeb [17]

Answer:

Step-by-step explanation:

3j = 27

j = 9

Jerry has 9 figures.

3 0

3 years ago

The measure of angle KMN = ?? degrees

Olegator [25]

∠KMN = (1/2)*arc KN . . . . . . this relationship is true of any inscribed angle. (It is a useful relationship to remember.)
  = 95°/2
  = 47.5°

5 0

3 years ago