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4 years ago

Define the variable plz ASAP!!!!

Mathematics

1 answer:

Ksivusya [100]4 years ago

4 0

There are 20 questions on the quiz.

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What word describes the equal shares of a shape

Sloan [31]

The word will depend on how many equal shares there are. For example, if there are two equal shares, you can say "halves"; if there are three equal shares, you can say "thirds"; if there are four equal shares, you can say "quarters," etc.

4 0

4 years ago

Read 2 more answers

Two angles are complementary. If one angle measures 25 degrees, what is the measure of the second angle?

Katena32 [7]

I believe it is c.155 degrees

4 0

4 years ago

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2. Tina had $10. She spent $6 at the movie. a) What fraction of the money was not used? b) Calculate the percentage of money not

gregori [183]

Answer:

a) 2/5

b) 40%

Step-by-step explanation:

Tina had $10.

10-6=4

4/10=2/5

2/5x20/20=40/100

=40%

Hope this helps :)

3 0

3 years ago

Solve: k = -45 ÷ (-15).<br> GIVING BRAINLIST!!!

DerKrebs [107]

Answer: k - 3

Step-by-step explanation:

i just used the rules for division, and removed the parentheses.

k = 45 / 15

once i got to here, i just did simple division. :)

k = 3

4 0

3 years ago

Read 2 more answers

The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 < x

grandymaker [24]

Solution :

Given :

$f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.$

1. Cumulative distribution function

$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$

$=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx$

$=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$

$=\frac{1}{450} \int_6^x (x^2-x) \ dx$

$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$

$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right]$

$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$

2. Mean $E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$

$=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\ dx$

$=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$

$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$

$=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) - \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right)$

$=\frac{1}{450} [4608 - 252]$

= 17.2857

5 0

3 years ago