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Tanya [424]
3 years ago
6

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP A

SAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

D.) the amount in the account increase by 4% each year

Step-by-step explanation:

Compound interest formula: P*(1+r/n)^(nt)

P=initial principal balance

r=interest rate

n=times applied per [time (eg year)]

t=number of time periods gone by

The expression: 2500(1.04)^x

The expression: 2500(1+1/25)^(nt)

1.04=1+1/25=increases by 4% each year

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I’m on a timer PLZ HELP
MariettaO [177]

Answer:

answer is b

Step-by-step explanation:

8 0
3 years ago
Which expressions are equivalent to 2^5•2^4? Check all that apply.
Maurinko [17]

Option A: 2^9

Option E: 2^{-2}.2^{11}

Option F: (2.2.2.2.2)(2.2.2.2)

Solution:

Given expression is 2^5.2^4.

To find which expression is equivalent to the given expression.

Option A: 2^9

Using exponent rule: a^b.a^c=a^{(b+c)}

2^5.2^4=2^{(5+4)}=2^9

Therefore 2^9 is equivalent to the given expression.

Option B: 2^{20}

It is not equivalent to the given expression.

Option C: 2.2^9

2.2^9=2^{(1+9)}=2^{10}

Therefore, It is not equivalent to the given expression.

Option D: 2^{10}.2^2

2^{10}.2^2=2^{(10+2)}=2^{12}

Therefore, It is not equivalent to the given expression.

Option E: 2^{-2}.2^{11}

2^{-2}.2^{11}=2^{(2-11)}=2^9

Therefore, It is equivalent to the given expression.

Option F: (2.2.2.2.2)(2.2.2.2)

(2.2.2.2.2)(2.2.2.2)=2^5.2^4

Therefore, It is equivalent to the given expression.

Hence option A, Option E and Option E are equivalent to the given expression.

3 0
4 years ago
Read 2 more answers
A child builds two wooden train sets. The path of one of the trains can be represented by the function y = 2cos2x, where y repre
Svet_ta [14]

Using a trigonometric equation, it is found that it will take 2.28 minutes until the two trains are first equidistant from the child.

<h3>What is the distance of each train to the child?</h3>

The distance of the first train is:

y_1 = 2\cos^{2}x

The distance of the second train is:

y_2 = 3 + \cos{x}

<h3>When are the trains equidistant to the child?</h3>

When y_1 = y_2, hence:

2\cos^{2}x = 3 + \cos{x}

The following substitution is made:

z = \cos{x}

Hence:

2z^2 = 3 + z

2z^2 - z - 3 = 0

Which is a quadratic equation with coefficients a = 2, b = -1, c = -3, hence:

\Delta = b^2 - 4ac = (-1)^2 - 4(1)(-3) = 13

z_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{1 + \sqrt{13}}{4} = 1.5

z_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{1 - \sqrt{13}}{4} = -0.65

Then, applying the trigonometric equation, considering that -1 \leq z \leq 1 due to the range of the cosine function:

z_2 = \cos{x_2}

x_2 = \arccos{z_2} = \arccos{-0.65} = 2.28

It will take 2.28 minutes until the two trains are first equidistant from the child.

You can learn more about trigonometric equations at brainly.com/question/2088730

8 0
3 years ago
Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
liberstina [14]
The general equation for height is:
h = -0.5gt^2 + (v0)t + h0, where g = -9.8 m/s^2 or -32 ft/s^2, v0 = initial velocity, and h0 = initial height.
1) h = -4.9t^2 + 19: -4.9 means the units are in meters, and 19 means that the initial height was 19 m, which is group C.
2) -16t^2 means the units are in feet, and 50t means that the initial velocity was 50 ft/s upwards. This is group B.
3) -16t^2 again means the units are in feet, and 50 means the initial height was 50 ft. This is group D.
4) -4.9t^2 means the units are in meters, and 19 is the initial height of 19 m. This is for group A.
8 0
3 years ago
Read 2 more answers
The triangles are similar.<br><br> What is the value of x?
qaws [65]
96/24 = 4

25*4=6x+28

72=6x

x=12
8 0
3 years ago
Read 2 more answers
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