Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
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<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.
The vertices of a square are its endpoints
The coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
The given parameters are:
Calculate the distance EF
So, we have:
Add 5 to the y-coordinates of E and F
Subtract 5 to the y-coordinates of E and F
Hence, the coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
There is no third pair
Read more about vertices at:
brainly.com/question/2791243
3 hours and 35 minutes.
2 hours and 50 minutes.
As both lines and triangles have to have complete 180 degrees, we can deduce that the other angle by C is 130 degrees, as 180-50 is 130. Then, we add 130 to the other 35 degrees we have in the triangle, resulting in 165 degrees. From there, as we know that triangles must have 180 degrees altogether, we can find the missing angle by calculating 180-165, which results in 15.
Therefore, we know that the missing angle is 15 degrees.
Answer is 15
A=1/2 bh
A=1/2 5(6)