Given that the<span> iq scores for large populations are centered at 100.
To get what percent of these 78 students have scores above 100 we conduct a normal distribution probability of the data.
P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
</span>
Answer:
the answer is 131.4
Step-by-step explanation:
32.85/3= 10.95
10.95×12= 131.4
S = Kt - 16t^2
<span>setting s = 550 </span>
<span>550 = Kt - 16t^2 </span>
<span>this will reach the highest point when v = 0 </span>
<span>t = K/32 </span>
<span>when t = K/32 </span>
<span>550 = K^2/32 - K^2/64 </span>
<span>K^2 = 550*64 </span>
<span>K = 187.62 ft/s</span>
Answer:
First one is 36 and second one is 324!!!
6*6= 36
7*6- 42
36+42= 78.
The fraction is 36/42.
