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2 years ago

Help plz solve these equations by completing the square x square + 12x =1

Mathematics

1 answer:

Hitman42 [59]2 years ago

3 0

Answer:

x = - 6 ± $\sqrt{37}$

Step-by-step explanation:

Given

x² + 12x = 1

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(6)x + 36 = 1 + 36

(x + 6)² = 37 ( take the square root of both sides )

x + 6 = ± $\sqrt{37}$ ( subtract 6 from both sides )

x = - 6 ± $\sqrt{37}$ ← exact solutions

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Read 2 more answers

Which expressions are equivalent to -6(b+2)+8−6(b+2)+8minus, 6, left parenthesis, b, plus, 2, right parenthesis, plus, 8 ? Choos

leva [86]

Answer:

B. $-6b-4$

Step-by-step explanation:

Given expression is $-6(b+2)+8$

Simplifying the expression now

Lets use distributive property of multiplication to solve it.

As given, $-6(b+2)+8$

Distributing -6 with b and 2.

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Opening the parenthesis

= $-6b-12+8$

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2 years ago

Please answer numbers 32 and 33! Please show work and explain your answer!

mrs_skeptik [129]

12.
Add like terms from both trinomials:

$4x^{2} + -2x^{2} = 2x^{2}$
$2x + -5x = -3x$
$-1 + 3 = 2$

Combine these terms to get a new trinomial as your answer:

$2x^{2} - 3x + 2$

13.
Subtract like terms from both trinomials (note that subtracting a negative is the same as adding it as a positive):

$3x^{2} - 5x^{2} = -2x^{2}$
$-8x - -11x = -8x + 11x = 3x$
$-1 - -1 = -1 + 1 = 0$

0 can be left out of the answer.

Combine these terms to get a binomial as your answer:

$-2x^{2} + 3x$

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2 years ago