What is the area of the trapezoid below?

Mathematics

2 answers:

wlad13 [49]3 years ago

5 0

Answer:

Step-by-step explanation:

vitfil [10]3 years ago

5 0

Answer:

The answer is 34.5cm2. (don't blame meh if wrong)

Step-by-step explanation:

Step 1: Find the area of the square; 4.6 x 3.2 = 14.72

Step 2: Find the bottom length to find the area of the triangle; 7.5 - 3.2 = 4.3

Step 3: Find the area of the triangle; 4.3 x 4.6 = 19.78

Step 4: Add the area of the square to the area of the triangle; 14.72 + 19.78 = 34.5

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A classmate plotted the following points:

irga5000 [103]

Answer:

D(-1,0)

Step-by-step explanation:

Plot points A(-3, 2), B(-1, 4), and C(1, 2) on the coordinate plane (see attached diagram).

Two sides AB and BC are of equal length and are perpendicular, because

$AB=\sqrt{(-3-(-1))^2+(2-4)^2}=\sart{(-2)^2+(-2)^2}=\sqrt{4+4}=2\sqrt{2}\ units\\ \\BC=\sqrt{(-1-1)^2+(4-2)^2}=\sart{(-2)^2+2^2}=\sqrt{4+4}=2\sqrt{2}\ units\\ \\\text{Slope AB}=\dfrac{4-2}{-1-(-3)}=\dfrac{2}{2}=1\\ \\\text{Slope BC}=\dfrac{2-4}{1-(-1)}=\dfrac{-2}{2}=-1\\ \\\text{Slope AB}\cdot \text{Slope BC}=1\cdot (-1)=-1\Rightarrow \text{lines AB and BC are perpendicular}$

If the quadrilateral ABCD has all sides perpendicular, then ABCD is a square. The diagonals of the square bisects each other. Find the coordinates of the point of intersection of these diagonals. This is the midpoint of segment AC:

$x=\dfrac{-3+1}{2}=-1\\ \\y=\dfrac{2+2}{2}=2$

If point O(-1,2) is the point of intersection of diagonals, then it is the midpoint of the diagonal BD. Find coordinates of point D:

$x_O=\dfrac{x_B+x_D}{2}\Rightarrow -1=\dfrac{-1+x_D}{2},\ -1+x_D=-2,\ x_D=-1\\ \\y_O=\dfrac{y_B+y_D}{2}\Rightarrow 2=\dfrac{4+y_D}{2}, 4+y_D=4,\ y_D=0$