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Ainat [17]
3 years ago
12

A healthcare professional might use many of the abbreviations on the "Do Not Use" list. The ones that I saw the most when workin

g as a pharmacy technician was HS, hs, q.d., QD, and cc. HS means half-strength and hs means at bedtime, q.d. and QD means every day but could be mistaken as q.i.d. and cc means cubic centimeters could be mistaken for u which is units.
Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

In this case, the abbreviation U, can be confused as a zero or the number four (4), which can result in an overdose. It could also be confused with "cc" (cubic centimeters) when spelled incorrectly.

Step-by-step explanation:

Medical terminology may seem like a complex foreign language, however it is the key to understanding the medical terms that focuses on its components (prefixes, roots and suffixes).

Technology plays a very important role in the provision of health care. Use technology properly, evaluating its effectiveness continuously. Although technology can reduce medication errors and improve patient safety, it also has the potential to cause unintentional errors.

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for every three short horned lizards there are two fence lizards. If there are 54 short horned lizards how many fence lizards ar
Komok [63]

Answer: 36

Step-by-step explanation:

54/3 = 18 x 2 = 36

8 0
3 years ago
Which ordered pair makes both inequalities true?
kow [346]

An ordered pair which makes both inequalities true is (-1, -3).

<h3>What is an ordered pair?</h3>

An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.

Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.

For ordered pair (-3, 5), we have:

y < –x + 1

5 < -(-3) + 1

5 < 3 + 1

5 < 4 (False).

For ordered pair (-2, 2), we have:

y < –x + 1

2 < -(-2) + 1

2 < 2 + 1

2 < 3 (True).

y > x

2 > -2 (True)

For ordered pair (-1, -3), we have:

y < –x + 1

-3 < -(-1) + 1

-3 < 1 + 1

-3 < 2 (True).

y > x

-3 > -1 (False)

For ordered pair (0, -1), we have:

y < –x + 1

-(-1) < -(0) + 1

1 < 1

1 < 1 (False).

y > x

-1 > 0 (False)

Read more on inequality here: brainly.com/question/27166555

#SPJ1

5 0
1 year ago
I GIVEEEEE BRAINLILSTTTTT
Anestetic [448]

Answer:

C(1,-2)

D(1,1)

E(2,-1)

4 0
3 years ago
Simplify: 27k^5m^8/(4k^3)(9m^2)
Yakvenalex [24]
The answer to your question is 3k^2m^6/4
4 0
3 years ago
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
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