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ddd [48]
3 years ago
14

add midnight the temperature was 14°F. By 5 AM the temperature had increased by 5°F. At noon the temperature had decreased by 20

°F, how much does the temperature need to rise or fall to return to the original temperature of 14°F
Mathematics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

It needs to rise by 15°F to get back to 14°F

Step-by-step explanation:

yes

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Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

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Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

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Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

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$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

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