Can someone please help me on this it’s due today

Mathematics

1 answer:

atroni [7]3 years ago

4 0

Answer:

the more predictions you make the more your answers will be correct over parabolas.

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What is the value of y so that the equation is true?

polet [3.4K]

Answer:

I guess that You made a mistake and You wanted to solve equations $\sqrt[2]{y}$ . Then the answer is D because There is no number that gives a negative number after the square root

Step-by-step explanation:

7 0

3 years ago

Can someone please clearly and correctly work out Q19? Would appreciate it a lot! :)

DiKsa [7]

$x^{2} +10x+30$
I always start by moving the last term to the other side
$x^{2} +10x=-30$
To complete the square you take term 'b' , divide it by 2 then square it
$( \frac{10}{2} )^2$ = 25
We have to add 25 to what we have and what you do to one side you have to do to the other
$x^{2} +10x+25=-30+25$
$x^{2} +10x+25=-5$
Now we factor what is on the left side of the equation
$(x+5)^2=-5$
The last step is to move our right side of the equation back over
$(x+5)^2+5$ - which is your answer :)))

6 0

3 years ago

Math IIIB Performance Task: Piecewise-Defined Functions

meriva

9514 1404 393

Explanation:

a) see the attachment for a graph (red curve)

b) The piecewise defined function can be ...

$\displaystyle C(x)=\begin{cases}0&0\le x\le 1\\5&1$

c) The new cost function is ...

$\displaystyle C(x)=\begin{cases}10&0\le x\le5\\x+5&5$

The charge is a flat $10 for any period up to 5 hours, then $1 per additional hour after that, prorated for partial hours. There is apparently no upper limit on parking time as there was with the original function. (The graph shown goes beyond 15 hours; the domain of the original C(x) is 0 to 12 hours.) For reference, the new cost structure is shown in blue in the attachment.

_____

<em>Additional comment</em>

Under the new structure, costs are significantly higher for short-term parking, and lower once the term exceeds 6 hours.