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Aloiza [94]
3 years ago
13

The price has changed from 125$ to 75$. By how much percent did it change

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

-40 %

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((75 - 125) / 125) * 100 = -40 %

The percentage change from 125 to 75 is -40 %

ohaa [14]3 years ago
5 0

Answer:

its -40 percent that's all :)

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The equation of the line that passes through (-2, -4) and (6’0)
STALIN [3.7K]

Answer:

y = 1/2x - 3

Step-by-step explanation:

y2 - y1 / x2 - x1

0 - (-4) / 6 - (-2)

4/8

= 1/2

y = 1/2x + b

0 = 1/2(6) + b

0 = 3 + b

-3 = b

8 0
3 years ago
WHAT WOULD THIS BEEEEEEE!!
miv72 [106K]

Answer:

c) 30

Step-by-step explanation:

since the lines are parallel, 75° = 2x + 15°

this is because when two parallels lines are intersected by the same line, all respective angles are equal. Also, opposite angles on a line are equal too.

So now that u have 75 = 2x + 15, just solve for x by simplifying:

75 = 2x + 15

60 = 2x

30 = x

so the answer is c) 30

hope this helps!

7 0
3 years ago
What is the answer for number six?
Anna71 [15]
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6 0
3 years ago
F is inversely proportional to d 2 . When F = 3 , d = 4 Work out F when d = 2
Natalka [10]

Answer:

F = 6

Step-by-step explanation:

find the constant of variation (k) first by using this formula:

f = k/d

plug in given info to find k:  3 = k/4 so k = 12

use 12 to find F:  F = 12/2

5 0
3 years ago
Kelly deposits $3,000 at a rate of 5.2% compounded quarterly. With no additional deposits or withdrawals, what is the account ba
lorasvet [3.4K]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 5.2\%\to \frac{5.2}{100}\to &0.052\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &10
\end{cases}
\\\\\\
A=3000\left(1+\frac{0.052}{4}\right)^{4\cdot 10}\implies A=3000(1.013)^{40}
\\\\\\
A\approx 5029.201878874637
7 0
3 years ago
Read 2 more answers
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