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DaniilM [7]
3 years ago
15

11. Which of these conditions would decrease the rate of photosynthesis in a plant?

Chemistry
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

B. Changing the daylight hours from 14 hrs to 10 hrs

Explanation:

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As refrigerant passes through the expansion valve, it cools down or heats up?
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It cools down i am 100 percent sure it cools down
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Explain the role light plays on the rate<br> of photosynthesis.
Luda [366]

Answer:

The process of photosynthesis occurs when green plants use the energy of light to convert carbon dioxide (CO2) and water (H2O) into carbohydrates. Light energy is absorbed by chlorophyll, a photosynthetic pigment of the plant, while air containing carbon dioxide and oxygen enters the plant through the leaf stomata.

5 0
3 years ago
Suppose 13L of gas is known to contain .965 Mol. If the amount of gas is Increased to 3.20 mol, what new volume will result? (Av
Ostrovityanka [42]

Answer &Explanation:

From Avogadro's lawa equal volume of gas contain equal number of moles

V=N

Hence

13L=965

XL=3.2mol

Hint:as the question state is increase to iteans final mol was 3.2 but if it could state by it would mean initial moles plus adde moles ie 3.2mol)

Cross multiplication

The new volume will be

=(3.2mol×13L÷965mol)

=0.043L

8 0
3 years ago
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^---------&gt;Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
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