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DaniilM [7]
3 years ago
15

11. Which of these conditions would decrease the rate of photosynthesis in a plant?

Chemistry
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

B. Changing the daylight hours from 14 hrs to 10 hrs

Explanation:

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A student reacts 0.600 g of lead (ii) nitrate with 0.850 g of potassium iodide
Fynjy0 [20]
Q1)
the reaction that takes place is 
lead nitrate reacting with potassium iodide to form lead iodide and potassium nitrate 
balanced chemical equation for the reaction is as follows
Pb(NO₃)₂ + 2KI ----> PbI₂  + 2KNO₃

Q2)
mass of lead nitrate present - 0.600 g 
number of moles = mass present / molar mass 
number of moles - 0.600 g / 331.2 g/mol = 0.00181 mol 

Q3)
mass of potassium iodide present - 0.850 g
number of moles = mass present / molar mass
number of moles of potassium iodide = 0.850 g / 166 g/mol = 0.00512 mol

Q4)
we have to calculate the number of moles of PbI₂ formed based on the number of moles of Pb(NO₃)₂ present assuming the whole amount of Pb(NO₃)₂ was used up 
stoichiometry of Pb(NO₃)₂ to PbI₂ is 1:1
number of Pb(NO₃)₂ moles reacted - 0.00181 mol
therefore number of PbI₂ moles formed - 0.00181 mol 


Q5)
next we have to calculate the number of moles of PbI₂ formed based on the amount of KI moles present , assuming all the moles of KI were used up in the reaction 
stoichiometry of KI to PbI₂ is 2:1
number of moles of KI reacted - 0.00512 mol
then number of moles of PbI₂ formed - 0.00512 x 2 = 0.0102 mol
0.0102 mol of PbI₂ is formed 

Q6)
limting reactant is the reactant that is fully consumed during the reaction. the amount of product formed depends on the amount of limiting reactant present

if lead nitrate is the limiting reactant 
if 1 mol of Pb(NO₃)₂ reacts with 2 mol of KI 
then 0.00181 mol of Pb(NO₃)₂ reacts with - 2 x 0.00181 mol of KI = 0.00362 mol 
but 0.00512 mol of KI is present and only 0.00362 mol are required 
therefore KI is in excess and Pb(NO₃)₂ is the limiting reactant 

Pb(NO₃)₂ is the limiting reactant 

Q7)
then the amount of PbI₂ formed depends on amount of Pb(NO₃)₂ present 
therefore number of moles of PbI₂ formed is based on number of Pb(NO₃)₂ moles present 
as calculated in Question number 4 - Q4
number of PbI₂ moles formed - 0.00181 mol 
mass of PbI₂ formed - 461 g/mol x 0.00181 mol = 0.834 g
mass of PbI₂ formed - 0.834 g

Q8) 
actual yield obtained  is not always equal to the theoretical yield . therefore we have to find the percent yield. This tells us the percentage of the theoretical yield that is actually obtained after the experiment
percent yield = actual yield / theoretical yield x 100 %
percent yield = 0.475 g / 0.834 g x 100 % = 57.0 %
percent yield of lead iodide is 57.0 %
6 0
3 years ago
A student is using a copper strip and a strong chlorine solution in her experiment. Which of these is a chemical property of one
Vsevolod [243]
A chemical property refers to that which cannot be physically determined. From the choices given above, the chemical property of one of the student's materials is the reactivity of the copper strip. Thus, the answer to this item is letter B. 
6 0
3 years ago
Read 2 more answers
Select the true statements regarding these resonance structures of formate.? Each carbon-oyxgen bond is somewhere between a sing
son4ous [18]

Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.

Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.

The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.

Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.

Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.

7 0
3 years ago
Read 2 more answers
. Write the following isotope in nuclide notation (e.g., “ ”): copper-70
vekshin1

Answer:

{\boxed{\text{$_{29}^{70}${Cu}}}

Explanation:

The atomic number (Z) of copper is 29 and this isotope has an atomic mass (A) of 70.

The general symbol for an isotope E is _{Z}^{A}\text{E}.

The atomic number is a left subscript, and the atomic mass is a left superscript.

\rm {\text{The nuclide notation for copper-70 is }}{\boxed{\textbf{$_{29}^{70}${Cu}}}

4 0
3 years ago
If bedrock has been partially weathered then what is it known as?
Black_prince [1.1K]
I think the correct answer from the choices listed above is the third option. If bedrock has been partially weathered then it is known as a regolith. Bedrock<span> can also become </span>regolith<span> as a result of mechanical </span>weathering. <span>It includes dust, soil, broken rock, and other related materials and is present on Earth, the Moon, Mars, some asteroids, and other terrestrial planets and moons.</span>
5 0
3 years ago
Read 2 more answers
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