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Hatshy [7]
3 years ago
10

Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^--------->Zn E°cell = -0.76 V Cu^2+ + 2 e^-----

----> Cu E°cell = 0.34 V 1. Predict the standard potential of the cell at 298 K. 2. What is the minimum voltage that should be applied to the standard electrolytic cell found in question to cause zn2+ to be reduced to Zn?
Chemistry
1 answer:
Neko [114]3 years ago
5 0

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

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For the reaction, 2A + B → 3C, rate of disappearance of A is 0.3 M/s in a certain time interval.What is the average rate of appe
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E) rate of appearance of C = 0.45 M/s

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<u>Rate of reaction</u> = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} → equation 1

Given that the rate of disappearance of A is 0.3 M/s

⇒ - \frac{d[A]}{dt} = 0.3 M/s

⇒Rate of reaction = - \frac{1}{2}\frac{d[A]}{dt} = \frac{1}{2}×0.3 M/s

⇒<u>Rate of reaction = 0.15 M/s</u>

From equation 1, \frac{d[C]}{dt} = - \frac{3}{2}\frac{d[A]}{dt} = \frac{3}{2}×0.3 M/s

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