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Hatshy [7]
3 years ago
10

Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^--------->Zn E°cell = -0.76 V Cu^2+ + 2 e^-----

----> Cu E°cell = 0.34 V 1. Predict the standard potential of the cell at 298 K. 2. What is the minimum voltage that should be applied to the standard electrolytic cell found in question to cause zn2+ to be reduced to Zn?
Chemistry
1 answer:
Neko [114]3 years ago
5 0

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

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A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration.
vodomira [7]

Answer:

16 liters of the solution with 40% concentration must be mixed with 62 liters of the solution with 25% concentration in order to obtain 78 liters, 25% concentration solution.

Explanation:

Let the required volume of solution 1 be represented by x.

The required volume of solution 2 would then be 78-x.

The number of moles of solution 1 that would be required = 0.4x

The number of moles of solution 2 that would be required = 0.25(78-x)

The number of moles of the final mixture = 78 x 0.28 = 21.84

moles of solution 1 + moles of solution 2 = moles of final mixture

0.4x + 0.25(78 - x) = 21.84

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     0.4x - 0.25x = 21.84 - 19.5

          0.15x = 2.34

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<em>Liters of 40% solution needed = 16 liters</em>

<em>Liters of 25% solution needed = 78 - 16 = 62 liters.</em>

<u>Hence, 16 liters of the solution with 40% concentration must be mixed with 62 liters of the solution with 25% concentration in order to obtain 78 liters, 25% concentration solution. </u>

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