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Hatshy [7]
3 years ago
10

Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^--------->Zn E°cell = -0.76 V Cu^2+ + 2 e^-----

----> Cu E°cell = 0.34 V 1. Predict the standard potential of the cell at 298 K. 2. What is the minimum voltage that should be applied to the standard electrolytic cell found in question to cause zn2+ to be reduced to Zn?
Chemistry
1 answer:
Neko [114]3 years ago
5 0

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

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Nuclear reaction takes place at the nucleus whereas chemical reaction involves valence electrons

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A cylinder and piston assembly (defined as the system) is warmed by an external flame. The contents of the cylinder expand, doin
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ΔE = 73 J

Explanation:

By the first law of thermodynamics, the energy in the system must conserved:

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So, Q = + 551 J, and W = + 478 J

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Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:
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The ground-state electron configurations of Cd^{2+} transition metal ions are diamagnetic [Kr] 4d^{10}. The ion is diamagnetic because there all electrons are paired.

<h3>What is Diamagnetic?</h3>
  • A magnetic field repels diamagnetic materials because it induces an opposing magnetic field in them when it is applied, which produces a repelling force.
  • In contrast, a magnetic field draws paramagnetic and ferromagnetic materials together.
  • All materials experience the quantum mechanical phenomenon known as diamagnetism, which is the only source of magnetism in a material.
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How many particles are in 13.5 grams of Beryllium ?
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4 0
3 years ago
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Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

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4 years ago
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