Answer:
the rate at which the height of the box is decreasing is -0.0593 cm/s
Step-by-step explanation:
Given the data in the question;
Constant Volume of a rectangular box with a square base = 500 cm³
area of the base increases at a rate of 6 cm²/sec
so change in the area of the base with respect to time dA/dt = 6 cm²/sec
each side of the base is 15 cm long
so Area of the base = 15 cm × 15 cm = 225 cm²
the rate at which the height of the box is decreasing = ?
Now,
V = Ah
dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0
⇒ dh/dt = -hdA/dt / A
we substitute
dh/dt = [ -( 500 / 225 ) × 6 ] / 225
dh/dt = [ -(2.22222 × 6) ] / 225
dh/dt = [ -13.3333 ] / 225
dh/dt = -0.0593 cm/s
Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s
